Question

Help me answer the question ​

Answer 1

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

• Revathi's age is 1/3 of her mother's age. If their difference in age is 24 years, find Revathi's age.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

Given,

• Mother's age = x
• Revathi's age = 1/3 x = ?
• Difference in their age = 24 years ⇨ x - 1/3 x = 24.

Now, let's solve this question using the above equation which we just formed.

$\sf \: x - \frac{1}{3}x = 24$

Combine x and $\sf\:-\frac{1}{3}x$ to get $\sf\frac{2}{3}x$.

$\sf\frac{2}{3}x=24$

Multiply both sides by $\sf\frac{3}{2}$, the reciprocal of $\sf\frac{2}{3}$.

$\sf \: x=24\times \left(\frac{3}{2}\right)$

Express $\sf24\times \left(\frac{3}{2}\right)$ as a single fraction.

$\sf \: x=\frac{24\times 3}{2}$

Multiply 24 and 3 to get 72.

$\sf \: x=\frac{72}{2}$

Divide 72 by 2 to get 36.

$\boxed{ \bf \: x=36 }$

We now have the age of Revathi's mother (x) = 36 years. Now, let's find Revathi's age ⇨ $\sf\:(\frac{1}{3}x)$

$\rightarrow \sf \: \frac{1}{3} x \\ \rightarrow \sf \: \frac{1}{3} \times 36 \\ \rightarrow \sf \: \frac{1}{ \bcancel 3} \times \bcancel{36} \\ \rightarrow \sf \:1 \times 12 \\ = \boxed{\boxed{\bf \: 12}}$

• So, Revathi is 12 years old.

Answer 2

Answer:

Step-by-step explanation:

let x be the mother's age and r be Revathi's age

x-r=24

r=x/3 or 3r=x

Revathi's age is (1/3)*x or x/3

we replace in the first equation x with 3 r

3r-r=24

2r=24

r=12 Revathi's age is 12

His mom is 36

the difference between their age is 36-12=24