The function is definately defined at x=0 but not x=1.
But its just one part of the coordinate (x,y).
If the value of y or f(x) is considered, you'll see that it is never possible to attain f(x)=0. In other terms (x,y)= (0,0) is not a defined point in the graph of the function because the graph doesnt pass through that point.
Now I hope you understood what I meant!
Conclusion- The above function is not defined at all points in the space having the abscissa or x=1 in the coordinate and also at ordinate or y=0 in the coordinate.nation:
Answer:
addition
Step-by-step explanation:
idkthis sounds dumb
D -2, 4 is in the second quadrant because the -x brings it to the left side and the positive 4 puts it in the upper of the left side which is the second quadrant
Answer:
1/6≈0.17≈17%
Step-by-step explanation:
