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Katyanochek1 [597]
4 years ago
8

What is the first incorrect justification? justification 3 justification 4 justification 2 justification 1?

Mathematics
1 answer:
marishachu [46]4 years ago
6 0
It should be Justification 2
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Find p.<br> 30°<br> O<br> 60°<br> 7 in
viva [34]

Answer:

p = 14 inches

Step-by-step explanation:

using either the sine or cosine ratios

using the sine ratio and the exact value

sin30° = \frac{1}{2} , then

sin30° = \frac{opposite}{hypotenuse} = \frac{7}{p} = \frac{1}{2} ( cross- multiply )

p = 14

5 0
2 years ago
Using the graph at the left, it shows the height h in feet
Nezavi [6.7K]

9514 1404 393

Answer:

  256 feet

Step-by-step explanation:

The vertex of the quadratic ax^2 +bx +c is found at x=-b/(2a). This means the time at which the rocket reaches it maximum height is ...

  t = -128/(2(-16)) = 4 . . . . seconds

Evaluating h at t=4 gives the maximum height:

  h = -16(4^2) +128(4) = -256 +512 = 256

The maximum height of the rocket is 256 feet.

_____

If you can read this value from "the graph at the left," you can save yourself some computation.

3 0
3 years ago
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nexus9112 [7]
$<span>3,170 is the answer</span>
7 0
3 years ago
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Multiply or divide as indicated. Leave your answer with no factors in the denominator. p⁻⁴q⁵r⁶/p⁻³qr⁻²
KIM [24]

Answer: \frac{q^4r^8}{p}

Step-by-step explanation:

By the Negative exponent rule, we know that:

a^{-1}=\frac{1}{a}

By the Quotient of powers property, we know that:

\frac{a^m}{a^n}=a^{(m-n)

And by the Product of powers property, we know that:

(a^m)(a^n)=a^{(m+n)}

Applying this properties, we get:

\frac{p^{-4}q^5r^6}{p^{-3}qr^{-2}}=\frac{p^3q^5r^6r^2}{p^4q}=\frac{q^4r^8}{p}

5 0
3 years ago
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What is 3a to the power of 4 times a to the power of 2
Harrizon [31]

Answer:ldk

Applying exponential property,  

Comparing the base,

Step-by-step explanation:

5 0
3 years ago
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