30 points

1 answer:

8 0

Since the rate of descent is a constant this is a linear equation and can be expressed as:

h=vt+b, where h=feet, v=slope or rate, b=y-intercept (y value when x=0 which is the initial height)

h=-2t+b, using the point (3,67) we can solve for b, or the initial height

67=-2(3)+b

67=-6+b

73=b so the initial height was 73 ft and the height equation is then:

h(t)=67-2t so when t=8 you have:

h(8)=67-2(8)

h(8)=67-16

h(8)=51 ft

You might be interested in

A bicycle wheel travels 321 in for each revolution. What is the radius of the wheel

Sliva [168]

Answer:

51.1 ≈ r

Step-by-step explanation:

"A bicycle wheel travels 321 in for each revolution"- means that 321 is the circumference of the wheel that is a circle.

C = 2· π· r

What is the radius of the wheel ?

321 = 2· π· r, divide both sides of the equation by 2 π

(321/2·π) = r , use calculator, solve and round the answer

51.1 ≈ r

4 0

2 years ago

In 2013 number of students in a small school is 284.it is estimated that student population will increase by 4 percent

BaLLatris [955]

The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.

Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get

{P}_{n} =284\cdot {1.04}^{n}P

=284⋅1.04

We can find the number of years since 2013 by subtracting.

\displaystyle 2020 - 2013=72020−2013=7

We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.

\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P

=284⋅1.04

≈374

The student population will be about 374 in 2020.

5 0

3 years ago

Soooo again in meters I'm soo sorryyy

vovikov84 [41]

I think 710 is the answer

266+266+89+89= 710

8 0

3 years ago

If a single card is drawn from a standard 52-card deck, what is the probability that it is an ace or a spade?

klasskru [66]

A 52-card deck is made up of an equal number of diamonds, hearts, spades, and clubs. Because there are 4 suits, there is a 1/4 chance to draw one of them, in our case, spades.

There are 4 aces in a 52-card deck, so the chance of drawing one is 4/52, or 1/13.

The question asks for the probability of drawing an ace or a spade. Because it uses the word "or," we add the probabilities together. This is because there is a chance of drawing either of the cards; it doesn't have to meet both requirements to satisfy the statement.

However, if the question were to say "and," we would multiply the two probabilities.

Let's add 1/4 and 1/13. First, we can find a common denominator. We can use 52 because both fractions can multiply into it (since the ratio came from a deck of 52 cards as well).

$\frac{1}{4} -- > \frac{13}{52}$