To set up your system of equations is to have 2 equations. They both would have 1 similar variable. For example, Jenny is 5 more her brother's age. She is also 2 more than twice her brother's age. You would set this up as Y, which is Jenny, and X, her brother. Y = 5 + x and Y = 2x + 2. Make sure you put Y in the same spot in both equations. Then take the other half of the equations and simplify them. 5 + x = 2x + 2. Subtract x from both sides to get 5 = x + 2. Subtract 2 from both sides to get 3 = x. Now replace the X from both equations to get Y = 5+3, and Y = 2(3) + 2. You will see both add up to 8, which is how old Jenny is in this example. Hope this helped!
The answer will be C
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5/2 , /5 , 2.71 (71 Repeating) , 2 3/4
Parallel lines have the same slope.
To compare the slopes of two different lines, you have to get
both equations into the form of
y = 'm' x + (a number) .
In that form, the 'm' is the slope of the line.
Notice that it's the number next to the 'x' .
The equation given in the question is y = 3 - 2 x .
Right away, they've done something to confuse you.
You always expect the 'x' term to be right after the 'equals' sign,
but here, they put it at the end. The slope of this line is the -2 .
Go through the choices, one at a time.
Look for another one with a slope of -2 .
Remember, rearrange the equation to read ' y = everything else ',
and then the slope is the number next to the 'x'.
Choice #4: y = 4x - 2 . The slope is 4 . That's not it.
Choice #3: y = 3 - 4x . The slope is -4 . That's not it.
Choice #2). 2x + 4y = 1
Subtract 2x from each side: 4y = 1 - 2x
Divide each side by 4 : y = 1/4 - 1/2 x .
The slope is -1/2. That's not it.
Choice #1). 4x + 2y = 5
Subtract 4x from each side: 2y = 5 - 4x
Divide each side by 2 : y = 5/2 - 2 x .
The slope is -2 .
This one is it.
This one is parallel to y = 3 - 2x ,
because they have the same slope.
Hello,
function minmax(int p1,int p2,int p3, int adr_big, int adr_small)
{ int mini=p1,maxi=p1;
if (p1>p2) {mini=p2;}
else {maxi=p2;};
if (p3>maxi) maxi=p3;
if (p3<mini) mini=p3;
*adr_big=maxi;
*adr_small=mini;
};
// main
int a=31,b=5,c=19,big,small;
minmax(a,b,c,&big,&small);
It's actually easier than it seems. if the tax is paid in equal payments every month and the total throughout a year (12 months) is $2,820, you have to find out how much they pay every month
so divide the total by the number of months
2,820/12=235
they pay $235 in taxes every month
to find out the total of the taxes and the house payment, just add the monthly tax and the monthly house payment.
235+752
and your answer is the sum
