Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.




Therefore, amount of the material left after 10 days would be 0.5 kg.





Therefore, amount of the material left after 20 days would be 0.25 kg.
Step-by-step explanation:
29x - 3 + 15x + 7 = 180° because these two angles are supplementary
if we add like terms
44x + 4 = 180
44x = 176 divide both sides by 44
x = 4
29x - 3 = 13y - 17 because alternate exterior angles has same measurement
since we found the value of x let's rewrite the equation
4 × 29 - 3 = 13y - 17
113 = 13y - 17
130 = 13y divide both sides by 13
10 = y
For some reason its not letting me send you it so like here is a pic
Step-by-step explanation:
we know,

Therefore, nth term of a given gp is
16a