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Inessa05 [86]
3 years ago
9

It is given that f(x) = 2x2 - 12x + 10.

Mathematics
1 answer:
Furkat [3]3 years ago
8 0

Answer:

a = 2, b = - 3, c = - 8

Step-by-step explanation:

Expand f(x) = a(x + b)² + c and compare coefficients of like terms, that is

a(x + b)² + c ← expand (x + b)² using FOIL

= a(x² + 2bx + b²) + c ← distribute parenthesis by a

= ax² + 2abx + ab² + c

Compare like terms with f(x) = 2x² - 12x + 10

Compare coefficients x² term

a = 2

Compare coefficients of x- term

2ab = - 12, substitute a = 2

2(2)b = - 12

4b = - 12 ( divide both sides by 4 )

b = - 3

Compare constant term

ab² + c = 10 , substitute a = 2, b = - 3

2(- 3)² + c = 10

18 + c = 10 ( subtract 18 from both sides )

c = - 8

Then a = 2, b = - 3, c = - 8

 

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3 0
3 years ago
Which of the following is not a disadvantage of using cash instead of credit?
sergeinik [125]

The <em>correct answer</em> is:

D) Using cash can make it easier to over-spend since you know exactly how much you have.

Explanation:

Knowing exactly how much you have on hand will actually help you avoid over-spending.

When using cash, you are aware of exactly how much money you have. With a credit card, this may not be the case; this makes it easier with a credit card to spend more money than you should for your budget. With cash it's easier to avoid this problem.

3 0
2 years ago
Read 2 more answers
What is 4(2×-7)+3(3×-1)=3(2-×)​
Mama L [17]

Answer:

x=37/20

Step-by-step explanation:

4(2x-7)+3(3x-1)=3(2-x)

8x-28+9x-3=6-3x

17x+3x=6+31

20x=37

8 0
3 years ago
Read 2 more answers
At the bakery ratio of cookie sales to donut sales is 4 to 3.Cookies and donuts cost the same amount.If the bakery earned 375.00
Oksanka [162]
3:7 = X:375
375/7 = 53.57
53.57×3 = 160.71
8 0
2 years ago
a team of 10 players is to be selected from a class of 6 girls and 7 boys. match each scenario to its probability
mars1129 [50]

Step-by-step explanation:

The selection of r objects out of n is done in

many ways.

The total number of selections 10 that we can make from 6+7=13 students is  

thus, the sample space of the experiment is 286

A.  

"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.

P(all 6 girls chosen)=35/286=0.12

B.

"The probability that a randomly chosen team has 3 girls and 7 boys."

with the same logic as in A, the number of groups were all 7 boys are in, is  

so the probability is 20/286=0.07

C.

"The probability that a randomly chosen team has either 4 or 6 boys."

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is 0.12.

case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls.  

the probability is 105/286=0.367

since  case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

D.

"The probability that a randomly chosen team has 5 girls and 5 boys."

selecting 5 boys and 5 girls can be done in  

many ways,

so the probability is 126/286=0.44

Did this help??

8 0
2 years ago
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