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slamgirl [31]
3 years ago
10

Gabriella needs a mason and must decide between 2 companies. For a service visit, Company A charges $65 to send a mason plus $30

/h. Company B charges $30
to send a mason plus $47.50/h. The graph that models this situation is shown here.

According to the graph, how many hours must the two masons work in order to charge the same amount of money?

_____ hour(s)

Mathematics
2 answers:
Allisa [31]3 years ago
8 0
By looking at were the two lines meet on the graph, they would both have to work for 2 hours to charge the same.
Kamila [148]3 years ago
7 0
So first we write out their respective charges
A=65+30x (x=hours of A)
B=30+47.5y (x= hours of B)

we want to know when A and B are equal so just set them to be equal

65+30x=30+47.5x
subtract 30 from both sides
35+30x=47.5x
multiplyboth sides by 2 to get rid of the nasty decimal
70+60x=95x
subtract 60x from both sides
70=35x
divide both sides by 35
2=x
they must work 2 hours for them to be equal

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3 years ago
How do you solve this?
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Answer:

Width: 7

Length: 14

Step-by-step explanation:

The area of a rectangle can be found my multiplying the length by the width. We do not know neither the length nor the width. However, we do know that the length is 7 feet longer than the width. Because we do not know the value of either side, let's let x represent the width.

Since the length is 7 feet longer, we can represent the length by x+7.

Now that we have our values for the length and the width we can multiply them together to find our area.

(x)(x+7)=x^{2} +7x

Now we have our equation, so we can address the changes made by the original question. The original question states that when 7 is added to both the length and width the area becomes 3 times larger. To do so simply increase each side by 7 by adding 7 to the original values.

(x+7)(x+14)

And multiply our area by 3.

3(x^{2} +7x)

set these equal to each other to find your new equation.

(x+7)(x+14)=3(x^{2} +7x)

Now you need to solve for x. To do this first muliply (x+7) and (x+14).

(x+7)(x+14)=\\x^{2} +14x+7x+98=\\x^{2} +21x+98

Then multiply 3(x^{2} +7x)

3(x^{2} +7x)=\\3x^{2} +21x

Now you can begin solving for x.

x^{2} +21x+98=3x^{2} +21x

Subtract x^{2} from both sides.

21x+98=2x^{2} +21x

Subtract 21x from both sides.

98=2x^{2}

Divide by 2.

49=x^{2}

And finally take the sqaure root of both sides.

\sqrt{x^{2} }=\sqrt{49}\\x=7

Remember, because we are dealing with length, there cannot be negative. So while normally we would get both +7 <em>and</em> -7, in this case we <em>only </em>get +7.

Now that we have the value of x, we can plug it into our original values.

For width we simply get 7.

For length we get 7+7=14

To check our answer we cna multiply 7 by 14 to get 98. Then we can add 7 to our length and width to get 14 and 21. Multiply these together and we get 294. 294 divided by 3 is 98, proving our answer correct.

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