Answer:
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 95
Given that the standard deviation of the Population = 5
Let 'X' be the random variable in a normal distribution
Let X⁻ = 96.3
Given that the size 'n' = 84 monitors
<u><em>Step(ii):-</em></u>
<u><em>The Empirical rule</em></u>


Z = 2.383
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = P(Z≥2.383)
= 1- P( Z<2.383)
= 1-( 0.5 -+A(2.38))
= 0.5 - A(2.38)
= 0.5 -0.4913
= 0.0087
<u><em>Final answer:-</em></u>
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
31-40. C. 12 students sold that many, therefore it's the most.
(a)
We can see that
this is a straight line
and this is the graph of velocity
we know that
acceleration is the derivative of velocity
so, slope of curve of velocity is acceleration
so, we will find slope of this line
We can select any two points
(0,4) and (5,7)
we can use slope formula

now, we can plug points


we know that slope of line is always constant irrespective of any value of t
so, acceleration will always be same irrespective of any value of t
so, we will get acceleration
............Answer
(b)
we can see that acceleration is constant
and we know that
derivative of constant is always 0
so, instantaneous rate of acceleration at t=10s is 0........Answer
Answer:
A. P' = (9, -2)
B. P" = (1, -4)
Step-by-step explanation:
To make it easier to understand, make point C the origin (0 , 0). From that, you will notice point P is 3 units right and 5 units up of point C, meaning the coordinates of point P is (3, 5). A 90° rotation clockwise on point P (3, 5) is (5, -3). Since point C is 4 units right and 1 unit up from the actual origin, we will add that to (5,-3); (5 + 4, -3 + 1) = (9, -2). Therefore, P' = (9, -2).
Knowing the coordinates of P' allows us to figure out the coordinates of P''. Once again, we'll make point C the origin, meaning P' would be at (5, -3). Like we did before, we will perform a 90° rotation clockwise of (5, -3) to get (-3, -5). Lastly, add back the appropriate amount of units to (-3, -5) to make point C the center of rotation in this example; (-3 + 4, -5 + 1) = (1, -4). Therefore, P" = (1, -4).
Please note that this is only my method of solving translations. Please consult more official sources if you want to learn more. Other than that, I hope this helps!