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patriot [66]
3 years ago
15

A principal of 5500 is invested in an account paying the amount of an annual rate of 5%. Find the amount in the account after 4

years if the account is compounded semi-annually, quarterly, and monthly.
Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0

Answer:

bnjkkkkkkkkkklllkkll

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56 is what percent of 80
Alik [6]

Answer:

70%

Step-by-step explanation:

Therefore, we can conclude that the required percentage is 70% that is 70% of 80 is 56.

<em>Hopes This Helps :)</em>

3 0
3 years ago
NEED ASAPPPP
Ber [7]

Answer:

(-3,4)

Step-by-step explanation:

to solve for x, make y=0

to solve for y, make x=0

3 0
3 years ago
Read 2 more answers
I think i have the right answer but I don’t know how to show my work/explanation, please help! *GRADE 9 WORK*
IrinaK [193]

Answer:

5 boys

Step-by-step explanation:

boys to girls in math class = 3/12

3/12 can be reduced to 1/4

In the science class, the ratio is the same but there is a total of 20 girls.

Multiply the fraction 1/4 by 2/2, 3/3, 4/4, 5/5, etc. until you get x/20. Then you have 20 girls. x is the number of boys.

1/4 = 2/8 = 3/12 = 4/16 = 5/20

In science the ratio of 1/4 is the same as 5/20, so there are 5 boys.

Answer: 5 boys

4 0
3 years ago
What is the answer to this question 1.6x + 30
PolarNik [594]
What are you trying to find ?
5 0
2 years ago
Cereal. A dietician obtains the amounts of sugar (incentigrams) from 100 centigrams (or 1 gram) in each of 10 differentcereals,
nadezda [96]

Answer:

Range is 44

mean is 29.7

variance is 289.56

standard deviation is 17.016

Step-by-step explanation:

The data given as follows

3, 24, 30, 47, 43, 7, 47,13, 44, 39

Range = maximum - minimum

             = 47 -3 = 44

mean = \frac{3+24+30+47+43+7+47+13+44+39}{10} = 297/10 = 29.7

variance = \frac{sum xi^2 }{N} - mean^2 }

              = 289.56

SD = \sqrt{variance}  = 17.016

The standard deviation of the given data is not a good measure as the range and standard deviation are far apart. The standard deviation gives how the given data is dispersed from the mean or expected value, while the range gives a rough idea of variability of the data.

3 0
3 years ago
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