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Lynna [10]
3 years ago
6

PLEASE HURRY In order to solve the system of equations below, Juana multiplies each equation by a constant to eliminate the y te

rms.
4x-3y = 1
5x+4y=9
What are the resulting equations?
16x-12y - 4
15x+12y - 27
16x-12y=-4
15x+12y = 27
16x-12y=-4
15x-12y = 27
Mathematics
2 answers:
Doss [256]3 years ago
7 0

Answer:

16x -12y = 4

15x +12y = 27

Step-by-step explanation:

4x-3y = 1

5x+4y=9

Multiply the first equation by 4

16x -12y = 4

Multiply the second equation by 3

15x +12y = 27

lbvjy [14]3 years ago
4 0

Answer:

16x - 12y = 4

15x + 12y = 27

Step-by-step explanation:

In order to eliminate the y terms, the equations must be manipulated in order to make the coefficient of the y-term equal 0 when the equations are added.

In this case, we are trying to make one equation with -3y and another equation with 4y result in a single equation with 0y.

We can do this by multiplying the first equation by 4 and the second equation by 3 to result in -12y and 12y. When these are added, the sum is 0y.

4 * (4x - 3y = 1) = 16x - 12y = 4

3 * (5x + 4y = 9) = 15x + 12y = 27

The resulting equations are

16x - 12y = 4

15x + 12y = 27

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Principle = 30,000<br>Time = 4 years<br>Rate = 30<br>Then find the simple interest ?​
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Answer:

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}

  • {\dashrightarrow \sf{Principle = Rs.30000}}
  • {\dashrightarrow \sf {Time = 4 \: years}}
  • \dashrightarrow \sf{Rate = 30\%}
  • \begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}

  • \dashrightarrow{\sf{Simple \: Interest }}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}

\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}

Where

  • \dashrightarrow{\sf{S.I = Simple \:  Interest }}
  • {\dashrightarrow{\sf{P = Principle }}}
  • {\dashrightarrow{\sf{ R = Rate }}}
  • {\dashrightarrow{\sf{T = Time}}}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{P \times R \times T}{100}}}}}}

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{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 120}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{3600000}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\cancel{\dfrac{3600000}{100}}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{Rs.36000}}}}}

{\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}

  • Henceforth,The Simple Interest is Rs.36000..

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}

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