Answer:
r = -12cos(θ)
Step-by-step explanation:
The usual translation can be used:
Putting these relationships into the formula, we have ...
(r·cos(θ) +6)² +(r·sin(θ))² = 36
r²·cos(θ)² +12r·cos(θ) +36 +r²·sin(θ)² = 36
r² +12r·cos(θ) = 0 . . . . subtract 36, use the trig identity cos²+sin²=1
r(r +12cos(θ)) = 0
This has two solutions for r:
r = 0 . . . . . . . . a point at the origin
r = -12cos(θ) . . . the circle of interest
Option D: is the x-coordinate
Explanation:
It is given that the coordinates of the line segment are A(3,2) and B(6,11).
Since, the line is partitioned by the point C by the ratio AC : BC = 2 : 3
The distance between the x-coordinates is 3 units.
To determine the value of the x-coordinate for point C, let us divide the value of x-coordinate from the ratio divided by the sum of ratio.
The value of x-coordinate from the ratio is 2.
Sum of the ratio is 2 +3 = 5
Thus,
The x - coordinate = value of x-coordinate from the ratio / Sum of ratio = 2/5
Substituting the values, we have,
The x - coordinate of the Point C =
Thus, Option D is the correct answer.
