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Semenov [28]
3 years ago
12

Help??????? It’s precal

Mathematics
2 answers:
Bond [772]3 years ago
8 0
ANSWER

\frac{F}{G} ( - 1) = - \frac{ 2}{ 3}

EXPLANATION

The given functions are:

F(x)=2x

and

G(x)= {x}^{2} + 2

\frac{F}{G} (x) = \frac{F(x)}{G(x)}

\frac{F}{G} (x) = \frac{2x}{ {x}^{2} + 2 }

Substitute x=-1

\frac{F}{G} ( - 1) = \frac{2( - 1)}{ {( - 1)}^{2} + 2 }

\frac{F}{G} ( - 1) = \frac{ - 2}{ 1+ 2 }

\frac{F}{G} ( - 1) = - \frac{ 2}{ 3}

The first choice is correct.
Mumz [18]3 years ago
6 0

what does precal mean I don't understand

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