Answer:
The third side must be 10: {3, 10, 10}; {10, 3, 3} is not possible.
Step-by-step explanation:
Everything depends on our understanding of "isosceles."
This term indicates that two sides of a given triangle are equal.
If two sides of an isosceles triangle have lengths of 3 and 10, then:
Either 1) Two sides have length 10 and the third side has length 3. This is certainly possible
or
2) sides have length 3 and the third side has length 10. This is NOT possible, since 3 + 3 adds up to 6, which is less than 10.
I’m pretty sure it’s -1
How you solve this is y2-y1/x2-x1
So 5-2/-3-1 which would be -1
∠ABC = ∠CDA (given)
∠BCA = ∠DAC (given)
CA = AC (common side)
ASA congruence criterion = when two angles of two triangles are equal and their included side is also equal, we can consider those triangles to be congruent to each other.
Since two angles in triangle △ABC and△CDA are equal and since their included side is also equal we can conclude that they are congruent.
Therefore, △ABC ≅ △CDA under the ASA congruence criterion.
Answer:
dufenschmertz evil incorporated...
Step-by-step explanation:
after hours ;)
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