<span>Northwest is 45 degrees north of west. If a car travels a distance x miles northwest, its northerly component gains x/sqrt(2) miles and its easterly component LOSES xsqrt(2)/ miles.
Resultant height is h = 4500 + 100x/sqrt(2) - 75x/sqrt(2) = [25/sqrt(2)]x + 4500
dh/dt = [25/sqrt(2)]dx/dt = [25/sqrt(2)]v </span>
First you need to see that this is a quadratic. I need.to put all of the values on one side of equation to see what I got.
6r^2 + 7r + 8 = 6
6r^2 + 7r + 2 = 0
Now this one is difficult to factor so i will use quadratic equation:
[-b (+-) sqrt (b^2 - 4ac)] / (2a)
we know that a b and c are in a quadratic at these positions.
ax^2 + bx + c
so
[-7 (+-) sqrt (7^2 -(4)(6)(2)] / (2) (6)
[-7 (+-) sqrt (49 - 48)] / 12
[-7 (+-) 1] /12
split into the + and - for 2 answers
(-7 + 1) / 12
-6/12
-1/2
And
(-7 -1) /12
-8 / 12
-2/3
those are.the 2 answers
But but it says largest so -1/2
Answer:5r2+2
Step-by-step explanation:
Distribute the Negative Sign:
=4r2−3r+2+−1(−r2−3r)
=4r2+−3r+2+−1(−r2)+−1(−3r)
=4r2+−3r+2+r2+3r
Combine Like Terms:
=4r2+−3r+2+r2+3r
=(4r2+r2)+(−3r+3r)+(2)
=5r2+2
80. there's no mathematical equations, also there's nothing to compare
Answer C cause I remember
