Cos (πt - 1) oscilates periodically between -1 and +1.
3Cos (πt - 1) oscilates periodically between -3 and +3.
The x-axis is the middle line. The equation of the x-axis is y = 0.
So the, the middle line is y=0.
Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
1512 I believe! :) I would double all the dimensions first, then multiply them all together.
Answer:
Where is the question?
Step-by-step explanation:
Answer:
Dimensions = 8 CM and 12 CM
length = 12 CM
width = 8 cm
perimeter = 2 ( length + width)
= 2( 12 + 8)
= 2 ( 20)
= 40 CM
ratio = 12/40
= 6/20
= 3/10
<h2>= 3 : 10 </h2>
