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kati45 [8]
3 years ago
6

3/8×24 tell me how u got it

Mathematics
2 answers:
Nady [450]3 years ago
4 0
(3/8)(24/1)=9
24*3= 72
8*1= 8
72/8=9
oee [108]3 years ago
4 0
9 because if you do 3/8 24 times you end with 9
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8 thousandths + 6 ones 8 thousandths= how many thousandths?
inna [77]

Consider 8 thousandths + 6 ones 8 thousandths

We have to determine the number of thousandths in the given number sentence.

8 thousandths = 0.008

6 ones 8 thousandths = 6.008

8 thousandths + 6 ones 8 thousandths = 0.008 + 6.008

= 6.016

So, the sum is 6.016

Therefore, there are 6 thousandths in the sum of the given numbers.

4 0
3 years ago
125 rounded to the nearest tenth
Lostsunrise [7]

130 is rounded to the nearest TENS

4 0
3 years ago
Three persons EB and C work together on a job and finish it finish it in 18 days if E and be working together can finish the job
nikitadnepr [17]

Answer:  30 days

<u>Step-by-step explanation:</u>

Working together, E & B get 1/45 of the job done per day

Working alone, C gets 1/x of the job done per day

Working together, E, B, & C get 1/18 of the job done per day.

EB:\dfrac{1}{45}\qquad C: \dfrac{1}{x}\qquad EBC:\dfrac{1}{18}\\\\\\\\EB+C=EBC\\\\ \dfrac{1}{45}\ +\dfrac{1}{x}=\dfrac{1}{18}\\\\\\(45\cdot 18\cdot x)\bigg(\dfrac{1}{45}+\dfrac{1}{x}=\dfrac{1}{18}\bigg)\\\\\\.\qquad \qquad 18x+810=45x\\\\.\qquad \qquad \qquad 810=27x\\\\.\qquad\qquad \qquad  \large\boxed{30=x}

7 0
3 years ago
2x+3=x+15<br>Help ASAP!​
stiv31 [10]
Answer: x=12

2x + 3 = x + 15
- 3 - 3
————————
2x = x +12
- x - x
—————
x = 12

5 0
3 years ago
Read 2 more answers
Consider the following functions. f1(x) = x, f2(x) = x2, f3(x) = 7x − 5x2 g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, a
Margaret [11]

Answer:

Therefore the solution is = k{-7,5,1} where k ∈R

Step-by-step explanation:

Given that,

f₁(x) =x

f₂(x)= x²

f₃(x)= 7x - 5x²

Also,

g(x) = c₁f₁(x)+c₂f₂(x)+c₃f₃(x)

Putting the values of f₁(x), f₂(x) and f₃(x).

g(x) = c₁.x+c₂x²+c₃(7x-5x²)

Given condition that g(x)= 0

∴ c₁.x+c₂x²+c₃(7x-5x²)=0

⇒(c₁+7c₃)x +(c₂-5c₃)x² = 0

Comparing the coefficients of x and x²

∴c₁+7c₃=0               and       c₂-5c₃ =0

\Rightarrow c_1 =-7c_3                     \Rightarrow c_2=5c_3

Let c₃= k   [k∈R]  

Then c₁ = -7k   and   c₂=5k

Therefore the solution is = { c₁,c₂,c₃}  

                                           = {-7k, 5k, k}

                                            =k{-7,5,1}

5 0
3 years ago
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