Answer:
When the element is not found we return -1.
Explanation:
When we use binary search we use BinarySearch() method of an array or list type when the element is found we return the index of the element if found if the element is not found we return -1.
We can decode this value since it is less than 0 and the indexing of arrays and lists starts with 0 upto the size-1.So -1 index is not present in the array or list.We have to check if the index is < 0 then the element is not present in the array or list.
for ex:-
if(index<0)
{
System.out.println("Element is not present in the array");
}
Answer:
The complete program is as follows:
def convert_distance(miles):
km = miles * 1.6 # approximately 1.6 km in 1 mile
return km
my_trip_miles = 55
# 2) Convert my_trip_miles to kilometers by calling the function above
my_trip_km =convert_distance(my_trip_miles) #3) Fill in the blank to print the result of the conversion
# 4) Calculate the round-trip in kilometers by doubling the result,
print("The distance in kilometers is " +str(my_trip_km))
# and fill in the blank to print the result
print("The round-trip in kilometers is " + str(my_trip_km * 2))
Explanation:
<em>The program is self-explanatory because I used the same comments in the original question.</em>
Answer:
The answer to the given question can be given as:
The value of *iptr is 7. and the value of iptr is dynamic.
Explanation:
In the c++ code, it is defined that x is an integer variable that assigns a value which is 7. Then we define a pointer variable that is *iptr. This variable holds an address of the x variable. When we print the value of the iptr variable. if we use the expression *iptr to print value of the pointer variable by cout that is used in c++ for pint values. so the value of the iptr is 7. If we use the expression iptr sent to cout so we show the address of the variable x. In the pointer, it manages the addresses of dynamically allocated so the address of the variable is changed on execution time.
