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oksian1 [2.3K]
3 years ago
9

Factor the expression. 36y^2 – 84y – 147

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
8 0
If you would like to factor the expression 36y^2 - 84y - 147, you can do this using the following steps:
<span>
36y^2 - 84y - 147 = 3 * (12y^2 - 28y - 49) = </span>3 * (6y + 7) * (2y - 7)

The correct result would be b. <span>3 * (6y + 7) * (2y - 7)</span>.
andrezito [222]3 years ago
7 0
3 (12y^2-28y-49)
3 (12y^2-42y+14y-49)
3(6y (2y-7)+7 (2y-7))
3 (2y-7)(6y+7)ans b
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Answer for a lot of points!
earnstyle [38]

Given :

  • ZC = 90°

  • CD is the altitude to AB.

  • \angleA = 65°.

To find :

  • the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> \angleCAB = 65°.

So,

=> \angleACB + \angleCAB+\angleZCBA = 180° (By angle sum Property.)

=> 90° + 65° + \angleCBA = 180°

=> 155° +\angleCBA = 180°

=> \angleCBA = 180° - 155°

=> \angleCBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> \angle CDB = 90°

=> \angleCBD = \angleCBA = 25°.

So,

=> \angleCBD + \angleDCB = 180° (Angle sum Property.)

=> 90° +25° + \angleDCB = 180°

=> 115° + \angleDCB = 180°

=> \angleDCB = 180° - 115°

=> \angleDCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> \angleADC = 90°

=>\angle CAD =\angle CAB = 65°.

So,

=> \angleADC + \angleCAD +\angleDCA = 180° (Angle sum Property.)

=> 90° + 65° + \angleDCA = 180°

=> 155° +\angleDCA = 180°

=> \angleDCA = 180° - 155°

=> \angleDCA = 25°

Hence, we get,

  • \angleDCA = 25°
  • \angleDCB = 65°
  • \angleCDB = 90°
  • \angleACD = 25°
  • \angleADC = 90°.
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