Write and algebraic expression for nine times of the square of a number
1 answer:
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Step-by-step explanation:
I think I'm a little too late to answer this question, but I'm still going to give you a basic sin function to show you where to find these things :)
I put the variables corresponding to their appropriate word.
(a=amplitude, p=period, s=shift)
You can find the amplitude <u>in front</u> of the sin (or cos, tan, cot, etc). The amplitude is always the first number presented in a trig function.
You find the period by taking the number paired with the x and dividing 2π by it. ( ) In this case, you're looking for a period of
which means that you would be dividing the 2π by 8 (
)
The shift is always added at the <u>end</u> of the function.
- For vertical shifts, the shift is added separately as it's own individual value. (A good example would be the last option in your sc; ).
- For horizontal shift, the shift is joined with the x in the parentheses. If you want to think about it this way, the horizontal axis is the x-axis. Therefore, it makes sense that if it's a horizontal shift, the shift will be with the x.
Using all this information, we can determine that the answer has to have a 6 in front of it, an 8 multiplied with the x, and a in parentheses with the x.
Your final answer should be the 3rd option,
Answer: