4 years ago

Can a y-intercept be a fraction in Slope intercept form

Mathematics

2 answers:

storchak [24]4 years ago

6 0

Yes, because a y-intercept can always be a fraction.

klasskru [66]4 years ago

5 0

No y should always be by itself

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Can you help me with this, please?

Aloiza [94]

Answer:

y =x-12

Step-by-step explanation:

$(x_1, y_1) = (16, 4) \ \ \ and \ \ \ (x_2, y_2) = (17, 5)$

Equation of straight line is

$y-y_1 =\frac{y_2-y_1}{x_2-x_1} (x-x_1)$

$y-4 =\frac{5-4}{17-16} (x-16)$

$y =(x-16)+4$

$y =x-12$

3 0

3 years ago

What is the solution to the system of equations? (7, 4) (7, startfraction 13 over 3 endfraction) (8, startfraction 14 over 3 end

miss Akunina [59]

The points are (7, 13/3).

Lets simplify the equation,

The equation of first line: y = 1/3 x + 2

the equation of second line: y= 4/3x - 5

Solve the system of equations by elimination,

Multiply equation A by -4 both sides

-4y = -4(1/3x +2)

-4y = -4/3x-8

After eliminating the equation we get,

y = 13/3

So now have to find x

13/3 = 1/3x + 2

Lets multiply above by 3
x = 13-6

x = 7.

Hence the points are (7, 13/3)

Learn more about Quadratic Equation on:

brainly.com/question/1214333

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5 0

2 years ago

2x + 3 = 5x - 2

Daniel [21]

Answer:

x3r9

Step-by-step explanation:

5 0

3 years ago

Please teach ne how to solve

Fofino [41]

To find the area you do A=bh(basexheight) 12x8=96

7 0

3 years ago

Solve for t. Please help asap!

yawa3891 [41]

Answer:

The answer is B.

$t=+\sqrt{\frac{d-3}{a} } , -\sqrt{\frac{d-3}{a}$

Step-by-step explanation:

$d=3+at^2\\\\d-3=at^2\\\\\frac{d-3}{a}=t^2\\\\ t=+\sqrt{\frac{d-3}{a} } , -\sqrt{\frac{d-3}{a} }$

5 0

3 years ago