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3 years ago

Can a y-intercept be a fraction in Slope intercept form

Mathematics

2 answers:

storchak [24]3 years ago

6 0

Yes, because a y-intercept can always be a fraction.

klasskru [66]3 years ago

5 0

No y should always be by itself

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In an exponential function like the one shown below, what does the a term and the b term

Ivenika [448]

The duma a term is the x interest

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2 years ago

The point (-3,-1) is the midpoint of (x,y) and (5,4). Find the point (x,y).

nirvana33 [79]

Answer:

(-11, -6)

Step-by-step explanation:

Find the distance between the midpoint, (-3, -1) and (5, 4). This can be calculated by finding the difference between the x coordinates and y coordinates.

-3 - 5 = -8 (distance between x coordinates)

-1 - 4 = -5 (distance between y coordinates)

Find the point (x, y) by subtracting 8 from the midpoint's x value, and then subtracting 5 from the midpoint's y value.

-3 - 8 = -11

-1 - 5 = -6

So, the point (x, y) is (-11, -6)

4 0

2 years ago

Please help for brainliest.

Kaylis [27]

Answer:

its C

Step-by-step explanation:

7 0

2 years ago

Please help

Harman [31]

Answer:

we get $\mathbf{gf(2)=-\frac{1}{3}}$

Step-by-step explanation:

We are given:

$f(x)=1-2x\\g(x)= \frac{1}{x}\\h(x)=x^3+1$

We need to find value of $gf(2)$

$gf(2)=g(f(2))$

First putting f(x) inside of g(x) and then putting x=2

$gf(x)=g(f(x))\\gf(x)=\frac{1}{1-2x}$

Now putting x=2 to find $gf(2)$

$gf(x)=\frac{1}{1-2x}\\gf(2)=\frac{1}{1-2(2)}\\gf(2)=\frac{1}{1-4}\\gf(2)=\frac{1}{-3}\\gf(2)=-\frac{1}{3}$

So, we get $\mathbf{gf(2)=-\frac{1}{3}}$

3 0

2 years ago

Which ordered pair describes point P? <br> A) -2, +4 <br> B) -2, -4 <br> C) +4, -2<br> D) -4, -2

zimovet [89]

The answer is a. (-2, 4). The horizontal line is the x-axis, and the vertical line is the y-axis, so the coordinate points would be (x, y) and (-2, 4) fit those coordinates. Hope this helps! :)

7 0

3 years ago

Read 2 more answers