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Bumek [7]
4 years ago
13

Check all of the following that are solutions to the system shown below.

Mathematics
1 answer:
loris [4]4 years ago
5 0
From second equation y = -2-x

Plug this into the first equation:-

- 2 - x = -x^2 - x + 2

x^2 + x - 2 - 2 - x = 0

x^2 - 4 = 0

x^2 = 4

x + +/- 2

Plug these values into x + y = -2 :-
x = 2:- 
2 + y = -2   

so y = -4 

so one solution is (2,-4)

Now try x = -2

- 2 + y = -2

y = 0 

so the second solution is ( -2 , 0)

So A and C  are correct
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50+30y

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The sum of two numbers is 31.The product of the two numbers is 150. What are the two numbers?
Nikolay [14]
The two numbers I will call x and y.
x + y = 31
x * y = 150

You then solve for one variable in either equation and substitute it into the other equation.

x + y = 31
x = 31 - y

Then you plug it in:
x * y = 150
(31 - y) * y = 150
-y² + 31y = 150
y² - 31y + 150 = 0            Then factor:
(y - 6)(y - 25) = 0
y - 6 = 0        y - 25 = 0
y = 6             y = 25

When you plug y into the original equations, it comes out that the two numbers are 6 and 25. You can check your work because 6+25 = 31 and 6*25 = 150. Hope this helps! :)
5 0
3 years ago
Which of the following is equivalent to the inequality shown below?
VARVARA [1.3K]

Answer:

4x + 0.9 \geq 0.1 is equivalent to the inequality 40x+9 \geq 1

Step-by-step explanation:

Given inequality : 4x + 0.9 \geq 0.1

We are supposed to find Which of the following is equivalent to the inequality

4x + 0.9 \geq 0.1

\Rightarrow 4x+\frac{9}{10} \geq \frac{1}{10}

Multiply both sides by 10

\Rightarrow 4(10)x+\frac{9}{10}(10) \geq \frac{1}{10}(10)

\Rightarrow 40x+9 \geq 1

4x + 0.9 \geq 0.1 is equivalent to the inequality 40x+9 \geq 1

So, Option B is true

B) 40x+9 \geq 1

7 0
3 years ago
One more for this find the slope stuff
sladkih [1.3K]

Solution given:

y=70x+\frac{82}{91}

Comparing above equation with y=mx+c

we get

m=70

So

<u>Slope</u><u>=</u><u>7</u><u>0</u>

8 0
3 years ago
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