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4 years ago

Check all of the following that are solutions to the system shown below.

1 answer:

5 0

From second equation y = -2-x

Plug this into the first equation:-

- 2 - x = -x^2 - x + 2

x^2 + x - 2 - 2 - x = 0

x^2 - 4 = 0

x^2 = 4

x + +/- 2

Plug these values into x + y = -2 :-
x = 2:-
2 + y = -2

so y = -4

so one solution is (2,-4)

Now try x = -2

- 2 + y = -2

y = 0

so the second solution is ( -2 , 0)

So A and C are correct

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I NEED HELP ASAP!!!!!! I WILL GIVE PRAILIEST TO THE CORRECT ANSWER

Norma-Jean [14]

-13 (q + 4) = 7q + 16

I think to solve it you do this first:

-13q + -52 = 7q + 16

And then I think you do:

-6q + -36

And thats all I can remember sorry ):

That -6q + -36 might be the answer I think (:

Hope I could help (:

3 0

3 years ago

Find the equation in standard form of the line passing through the points 3,-4 and 5,1

aliina [53]

Answer:

5x - 2y - 23 = 0

Step-by-step explanation:

Line is passing through the points $(3,\:-4)= (x_1, \:y_1) \: \&\: (5,\: 1)= (x_2,\:y_2)$

Equation of line in two point form is given as:

$\frac{y -y_1 }{y_1 -y_2 } = \frac{x -x_1 }{x_1 -x_2 } \\ \\ \therefore \: \frac{y -( - 4) }{ - 4 -1} = \frac{x -3 }{3 -5 } \\ \\ \therefore \:\frac{y + 4 }{ - 5} = \frac{x -3 }{ - 2 } \\ \\ \therefore \: \frac{y + 4 }{ 5} = \frac{x -3 }{ 2 } \\ \\ \therefore \: 2(y + 4) = 5(x - 3) \\ \therefore \: 2y + 8 = 5x - 15 \\ \therefore \: 5x - 15 - 2y - 8 = 0 \\ \red{ \boxed{ \bold{\therefore \: 5x - 2y - 23 = 0}}} \\ is \: the \: required \: equation \: of \: line \: in \: \\ standard \: form.$

7 0

3 years ago

Bob bought a bike for $250 and repaired it . He can now sell the bike for $300. What is the percent increase in the value bike ?

alexgriva [62]

Answer:20%

Step-by-step explanation:

250*20%=50

50+250=300

7 0

3 years ago

Which value, when placed in the box, would result in a system of equations with infinitely many solutions? y = -2x 4 6x 3y =

wariber [46]

The missing value is 12 in a system of equations with infinitely many solutions conditions.

It is given that in the system of equations there are two equations given:

$\rm y =n -2x+4\\\rm and \\\rm 6x+3y= ?$

It is required to find the missing value in the second equation.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables if we plot the graph of the linear equation we will get a straight line.

We have equations:

$\rm y = -2x+4 ....(1)\\ \\\rm 6x+3y= ? ....(2)$

Let's suppose the missing value is 'Z'

We know that the two pairs of equations have infinitely many solutions if and if they have the same coefficients of variables and the same constant on both sides.

From equation (1)

$\rm y = -2x+4 \\\\\rm 2x+y=4$ (multiply both the sides by 3)

$\rm 6x+3y=12$ ...(3)

By comparing the equation (2) and (3), we get

M = 12

Thus, the missing value is 12 in a system of equations with infinitely many solutions conditions.

Learn more about the linear equation.

brainly.com/question/11897796

8 0

2 years ago

PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

mash [69]

Answer:

(-6,9,-3)

Step-by-step explanation:

-3x -y +z=6

-3x-y+3z =0

x-3z =3

Multiply the second equation by -1

-1 *(-3x-y+3z) =0*-1

3x +y -3z =0

Add this to the first equation

-3x -y +z=6

3x +y -3z =0

----------------------

0 + 0 + -2z = 6

Divide by -2

-2z/-2 = 6/-2

z = 6/-2

z=-3

Take the third equation to find x

x-3z=3

x-3(-3) = 3

x+9=3

Subtract 9 from each side

x+9-9 =3-9

x=-6

Now we need to find y

3x +y -3z =0

3(-6) +y -3(-3) =0

-18 +y +9=0

-9+y =0

Add 9 to each side

-9+9+y = 0+9

y=9

(-6,9,-3)

3 0

3 years ago

Read 2 more answers