Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer:
<h2>22 hours and 10 hours </h2>
Step-by-step explanation:
let the jobs be x and y, so that
x+y=32--------1
9x+7y=248----2
x=32-y
substitute x=32-y for x in equation 2 we have
9(32-y)+7y=248
open bracket we have
288-9y+7y=248
-2y=248-288
-2y=-40
2y=40
divide both sides by 2 we have
y=40/2
y= 10 hours
subtitute y=10 for y in equation 1 to find x
x+10=32--------1
x=32-10
x=22
x=22 hours
1/6 x 54 = 9
Hope this helps ;)
Fifteen thousand six-hundred and thirty-eight
