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AlexFokin [52]
3 years ago
5

Radioactive Decay Beginning with 16 grams of a radioactive element whose half -life is 30 years ,the mass y(in grams) remaining

after t years is given by
y=23(1/2)^t/45, t ≥ 0.
How much of the initial mass remains after 150 years?
Mathematics
1 answer:
Flura [38]3 years ago
5 0

Answer:

the equation should be corrected to fit the data of the problem.  With the corrected equation a mass of 0.5 grams remains after 150 years

Step-by-step explanation:

for the mass y( in grams)

y=23* (1/2)^(t/45), t ≥ 0.

the initial mass is at t=0 , then

y= 23 grams  → should be 16 grams

half-life from the equation = 45 years → should be 30 years

the correct equation should be

y=16*(1/2)^(t/30), t ≥ 0

then after 150 years  → t= 150

y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams

then a mass of 0.5 grams remains after 150 years

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(1.2 x 10^13) - (4 x 10^11)
Alexandra [31]

Answer:

the answer is 11,600,000,000,000

Step-by-step explanation:

pemdas

(1.2 x 10 ^13) - (4 x 10 ^11)

10^13 = 10,000,000,000,000 put that in scientific notation to make it simpler do same for 10 ^11

10 x 10^13

(1.2 x 10 x 10^13) - ( 4 x 10 x 10^11)

now solve the first equasion

12,000,000,000,000 - 400,000,000,000

subtract

11,600,000,000,000

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3 years ago
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Find the Area of the figure below, composed of a rectangle and a semicircle. Round to the nearest tenth place.
kap26 [50]

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<h2>Question:</h2>

1) It's February and you go to the store to buy some food for your pets. You have a Great

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