The quotient of 5 1/4 and 3/16 is 28
Answer:
200,000
Step-by-step explanation:
its easy and simple lol
Answer:
1.) The product of 12 and 3/4 is less than 12. This is because you are multiplying 12 by a number less than 1.
2.) The product of 5 and 1/2 is less than 5, this is because you are multiplying 5 by a number less than one.
Step-by-step explanation:
If multiplied by a number less than one then it will be smaller than original
If multiplied by one will be the same as original
If multiplied by a number greater than one it will be greater than original
Answer:
Option: B
There are three times as many participants in the 40-59 age group than in the 0-19 age group.
Step-by-step explanation:
From the histogram we have following observations:
Number of people in the age group 0-19= 20
Number of people in the age group 20-39=40
Number of people in the age group 40-59=60
Number of people in the age group 60-79=50
Hence, from the data we could say that there are three times as many participants in the 40-59 age group( which is 60) than in the 0-19 age group(which is 20).
Hence, option B is correct.
Answer
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
Given,
∠BCE=28° ∠ACD=31° & line AB=AC .
According To the Question,
- a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°
- b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚
thus , ∠ABC=76° .
- c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,
Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°
Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)
∠DAB = 180° - 107° ⇔ 73°
& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°
Now, In Triangle ADC Sum of angles in a triangle is 180°
∠ADC = 180° - (31° + 45°) ⇔ 104˚
- d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre
For Diagram, Please Find in Attachment