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Anettt [7]
3 years ago
7

Quintin divided 5/20÷5/11 what answer would make a quintin correct

Mathematics
2 answers:
Paladinen [302]3 years ago
6 0

Answer:

it would be 11/20

Step-by-step explanation:

harina [27]3 years ago
4 0

Answer:

55/100

Look image below for explanation! Hope it helps! :)

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10 ft area of base 62ft 2 (squared)
AleksAgata [21]

Answer:

12

Step-by-step explanation:

3 0
3 years ago
A car starts with a speed of 20km/ hr and accelerates at a rate of 3.4 m/s for 20 seconds. What is the final speed of the car in
Schach [20]

The relevant formula that we can use in this situation is:

v = v0 + at

where v is the final velocity, v0 is the initial velocity = 20 km/hr, a is acceleration at 3.4 m/s^2 and t is time at 20 seconds

First convert v0 to m/s, v0 = 5.56 m/s

v = 5.56 m/s + 3.4 m/s^2 * 20 s

v = 73.56 m/s

Then convert back to km/hr:

<span>v = 264.82 km/hr</span>

5 0
3 years ago
When 50 pounds of a compound are produced, the manufacturing cost is described by x
Paraphin [41]

Answer:

56

Step-by-step explanation:

i don't know

4 0
3 years ago
Gil aunt cut his birthday cake into 32 equal pieces. eighteen pieces were eaten at his birthday party.what fraction of the cake
klasskru [66]
Started out with 32/32. They ate 18/32, 32-18=14; 14/32. To simplify, 7/16 was left.
8 0
3 years ago
25. Michael is studying population changes in two
g100num [7]

Answer: Average rates of change for Bird A is 0.045 and for Bird B is 3.816.

Step-by-step explanation: Through its graph, a function can be analyzed and be identified its attributes. Average Rate of Change is the ratio of change in the function values to the change of x-value, i.e., it is the slope of the function in a specific interval of x. With the Average it is possible to compare two function.

<u>Average Rate of Change</u>

<em><u>Bird A</u></em>:

For the interval [0,18]:

x₁ = 0 f(0) = 8.3

x₂ = 18 f(18) = 9.1

Average = \frac{f(18) - f(0)}{x_{2} - x_{1} }

Average = \frac{9.1 - 8.3}{18 - 0}

Average = 0.045

<em><u>Bird B</u></em>: y = 3.6(1.06)x

For the interval [0,18]:

x₁ = 0 y = 3.6(1.06)0 = 0

x₂ = 18 y = 3.6(1.06)18 = 68.7

Average = \frac{f(18) - f(0)}{x_{2} - x_{1} }

Average = \frac{68.7 - 0}{18 - 0}

Average = 3.816

The Average Rate for Change for Bird A is 0.045 and for Bird B is 3.816. This means that the population of Bird B increase in rate faster than the population of Bird A.

4 0
3 years ago
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