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Serga [27]
3 years ago
10

What common communication devices are used in homes to connect to the internet and remote networks and what capabilities do thes

e devices provide?
Computers and Technology
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

A device is indeed a computer unit that can relay a signal throughout the phone, any contact cable or wirelessly. A modem is the best illustration of such a device of communication.

Explanation:

A device that transforms a computer's signals and transmits data over cell towers, known as Modem.

It stands for "Modulator and Demodulator" and are of two types such as: Internal and External. It is being used for accessing the site that modulates carrier tides to encode the transmitting data as well as demodulates arriving waves to decode the documentation they hold.

Other means of communication shall include:

  • Routers.
  • Hub.
  • Switch.
  • Bridge.
  • Network cards.

So, it's the right answer.

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Hello, my first time being here and I'm returning back from college and I'm now studying Java in college but I was stuck doing t
KengaRu [80]

Answer:

import java.time.LocalDate;

class TestWedding {

 public static void main(String[] args) {

   Person man1 = new Person("John", "Doe", LocalDate.parse("1990-05-23"));

   Person woman1 = new Person("Jane", "Something", LocalDate.parse("1995-07-03"));

   Person man2 = new Person("David", "Johnson", LocalDate.parse("1991-04-13"));

   Person woman2 = new Person("Sue", "Mi", LocalDate.parse("1997-12-01"));

   Couple cpl1 = new Couple(man1, woman1);

   Couple cpl2 = new Couple(man2, woman2);

   Wedding wed1 = new Wedding(cpl1, "Las Vegas", LocalDate.parse("2020-09-12"));

   Wedding wed2 = new Wedding(cpl2, "Hawaii", LocalDate.parse("2021-01-02"));  

   displayDetails(wed1, wed2);

 }

 public static void displayDetails(Wedding w1, Wedding w2) {

   System.out.println(w1.toString());

   System.out.println(w2.toString());

 }

}

---------------------------

class Couple {

 private Person person1;

 private Person person2;

 public Couple(Person p1, Person p2) {

   person1 = p1;

   person2 = p2;

 }

 public String toString() {

   return person1.toString() + " and " + person2.toString();

 }

}

----------------------------

import java.time.LocalDate;

import java.time.format.DateTimeFormatter;

class Person {

 private String firstName;

 private String lastName;

 private LocalDate birthDate;

 public Person(String first, String last, LocalDate bdate) {

   firstName = first;

   lastName = last;

   birthDate = bdate;

 }

 public String getFirstName() {

   return firstName;

 }

 public String toString() {

   DateTimeFormatter formatter = DateTimeFormatter.ofPattern("LLLL dd, yyyy");

   return String.format("%s %s born %s", this.firstName, this.lastName, birthDate.format(formatter));

 }

}

------------------------------------

import java.time.LocalDate;

import java.time.format.DateTimeFormatter;

class Wedding {

 private Couple couple;

 private String location;

 private LocalDate weddingDate;

 public Wedding(Couple c, String loc, LocalDate wDate) {

   couple = c;

   location = loc;

   weddingDate = wDate;

 }

 public String getLocation() {

       return this.location;

 }

 public String toString() {

   DateTimeFormatter formatter = DateTimeFormatter.ofPattern("LLLL dd, yyyy");

   return  

     couple.toString() +  

     " are getting married in " + location + " on "+

     weddingDate.format(formatter);

 }

}

Explanation:

I used overrides of toString to let each object print its own details. That's why this solution doesn't really require any getters. I implemented some to show how it's done, but you'll have to complete it. The solution shows how to think in an OO way; ie., let every class take care of its own stuff.

6 0
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Answer:

boolean isEven = false;

if (x.length % 2 == 0)

isEven = true;

Comparable currentMax;

int currentMaxIndex;

for (int i = x.length - 1; i >= 1; i--)

{

currentMax = x[i];

currentMaxIndex = i;

for (int j = i - 1; j >= 0; j--)

{

if (((Comparable)currentMax).compareTo(x[j]) < 0)

{

currentMax = x[j];

currentMaxIndex = j;

}

}

x[currentMaxIndex] = x[i];

x[i] = currentMax;

}

Comparable a = null;

Comparable b = null;

if (isEven == true)

{

a = x[x.length/2];

b = x[(x.length/2) - 1];

if ((a).compareTo(b) > 0)

m = a;

else

m = b;

}

else

m = x[x.length/2];

8 0
3 years ago
What is the output when you run the following program? print(3 + 7) print("2 + 3")
QveST [7]

print(3+7) will output 10, which is an integer.

print("2+3") will output 2+3, which is a string.

6 0
3 years ago
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