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laila [671]
3 years ago
10

Eli wants to plant 45 sunflower plants, 81 corn plants and 63 tomato plants in his garden. If he put the same number of plants i

n each row and each row has only one type of plant, what is the greatest number of plants I can put in one row? Do I use GCF or LCM to solve this question?
Mathematics
1 answer:
Lynna [10]3 years ago
4 0

Answer:

9

Step-by-step explanation:

For this problem, you would use the GCF

Find the GCF of 45, 81, 63

GCF(45, 81, 63) = 9

45 = 9 * 5

81 = 9 *9

63= 9 * 7

Since 5, 9, 7 have no common factors, the GCF has to be 9.

This means that the greatest number of plants he can put in each row is 9.

The number of rows he uses for each plant will (obviously) vary.

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Given P = x^0.3 y^0.7 is the chicken lay eggs production function, where P is the number of eggs lay, x is the number of workers
lora16 [44]

Answer:

Part A)

\displaystyle \frac{dy}{dx}=-\frac{3}{7}P^\frac{10}{7}x^{-\frac{10}{7}}

Part B)

The daily operating cost decreases by about $143 per extra worker.

Step-by-step explanation:

We are given the equation:

\displaystyle P=x^{\frac{3}{10}}y^{\frac{7}{10}}

Where <em>P</em> is the number of eggs laid, <em>x</em> is the number of workers, and <em>y</em> is the daily operating budget (assuming in US dollars $).

A)

We want to find dy/dx.

So, let’s find our equation in terms of <em>x</em>. We can raise both sides to 10/7. Hence:

\displaystyle P^\frac{10}{7}=\Big(x^\frac{3}{10}y^\frac{7}{10}\Big)^\frac{10}{7}

Simplify:

\displaystyle P^\frac{10}{7}=x^\frac{3}{7}y

Divide both sides by<em> </em>the <em>x</em> term to acquire:

\displaystyle y=P^\frac{10}{7}x^{-\frac{3}{7}}

Take the derivative of both sides with respect to <em>x: </em>

\displaystyle \frac{dy}{dx}=\frac{d}{dx}\Big[P^\frac{10}{7}x^{-\frac{3}{7}}\Big]

Apply power rule. Note that P is simply a constant. Hence:

\displaystyle \frac{dy}{dx}=P^\frac{10}{7}(-\frac{3}{7})(x^{-\frac{10}{7}})

Simplify. Hence, our derivative is:

\displaystyle \frac{dy}{dx}=-\frac{3}{7}P^\frac{10}{7}x^{-\frac{10}{7}}

Part B)

We want to evaluate the derivative when <em>x</em> is 30 and when <em>y</em> is $10,000.

First, we will need to find <em>P</em>. Our original equations tells us that:

P=x^{0.3}y^{0.7}

Hence, at <em>x</em> = 30 and at <em>y</em> = 10,000, <em>P </em>is:

P=(30)^{0.3}(10000)^{0.7}

Therefore, for our derivative, we will have:

\displaystyle \frac{dy}{dx}=-\frac{3}{7}\Big(30^{0.3}(10000^{0.7})\Big)^\frac{10}{7}\Big(30^{-\frac{10}{7}}\Big)

Use a calculator. So:

\displaystyle \frac{dy}{dx}=-\frac{1000}{7}=-142.857142...\approx-143

Our derivative is given by dy/dx. So, it represents the change in the daily operating cost over the change in the number of workers.

So, when there are 30 workers with a daily operating cost of $10,000 producing a total of about 1750 eggs, the daily operating cost decreases by about $143 per extra worker.

5 0
2 years ago
Does any body know the answer??
Mashcka [7]
Angle V is 40. Angle V and Y are congruent. The angles of a triangle are a sum of 180. Angle V and Angle Y add up to 80. Therefore angle VWZ is 100
8 0
3 years ago
If a median, an altitude, and an angle bisector are the same segment in a triangle, the triangle is scalene
statuscvo [17]
Never is the right answer .
3 0
3 years ago
What to write it here
Orlov [11]

Answer:

84 degrees

Step-by-step explanation:

Angle A = 83 degrees

Angle B = x degrees

Angle C = 135 degrees

Angle CDE = 122 degrees

We know that the four inner corners of a quadrilateral should add up to 360 degrees. Two supplementary angles will add up to 180 degrees. Adjacent angles on a straight line will always be supplementary. Knowing this, just solve for <ADC and add that amount to <A and <C. Then, subtract that sum from 360 degrees.

<ADC = 180-122 = 58

58+83+135 = 276

360-276 = 84 degrees

7 0
2 years ago
2√64<br> (+) =8<br> 10-2 <br><br>solve 3√125=? by following steps above​
Liono4ka [1.6K]

<em><u>your </u></em><em><u>question:</u></em><em><u> </u></em>

solve 3√125=? by following steps above

<em><u>answer:</u></em>

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