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laila [671]
3 years ago
10

Eli wants to plant 45 sunflower plants, 81 corn plants and 63 tomato plants in his garden. If he put the same number of plants i

n each row and each row has only one type of plant, what is the greatest number of plants I can put in one row? Do I use GCF or LCM to solve this question?
Mathematics
1 answer:
Lynna [10]3 years ago
4 0

Answer:

9

Step-by-step explanation:

For this problem, you would use the GCF

Find the GCF of 45, 81, 63

GCF(45, 81, 63) = 9

45 = 9 * 5

81 = 9 *9

63= 9 * 7

Since 5, 9, 7 have no common factors, the GCF has to be 9.

This means that the greatest number of plants he can put in each row is 9.

The number of rows he uses for each plant will (obviously) vary.

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What is the second term in the binomial expansion of (2r-3s)12?
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Max was on vacation twice as long is Jared and half as long as Wesley. The boys were on vacation a total of three weeks. How man
nasty-shy [4]
To begin with, the question is asking for the answer in days, so let's change 3 weeks to days. There are 7 days in 1 week; 3 weeks times 7 days = 21 days.
21 total days of vacation.

Max + Jared + Wesley = 21 days
(Let's use the first letter of their name to represent their vacation time)

M + J + W = 21 [This is the equation we'll be coming back to]

Now, we can use the clues given in the question to have an equation for each variable/boy. 

Max was on vacation twice as long as Jared. We can interpret this as  M= 2J Max was on vacation only half as long as Wesley. We can interpret this as M = (1/2)W.

So far we have these three equations: M + J + W = 21M = 2J M = (1/2)W

To have an equation for each individual boy, we must rearrange the last two equations in the list.

First, M = 2J.
Divide both sides by 2
M/2 = 2J/2
(1/2)M = J

Second, <span>M = (1/2)W
Multiply both sides by 2
2M = W

New equations:
</span><span>M + J + W = 21 [From the old list]
</span>J = (1/2)W
W = 2M

Now we can substitute the last two equations into the first one. 
M + J + W = 21
M + (1/2)W + 2M = 21
[Combine Like Terms]
<span>(7/2)M = 21 
</span>
Then, solve for M (Max's vacation days):
Multiply both sides by 2/7
(\frac{2}{7})* (\frac{7}{2}m)= (\frac{2}{7})*(21)
M = 6

Now we know Max was on vacation for 6 days.

If Max was on vacation twice as long as Jared, that means Jared was on vacation HALF as long as Max.

So...
<span>J = (1/2)M 
J = (1/2) * 6
J = 3
Jared was on vacation for 3 days 
</span>
Wesley was on vacation twice as long as Max so...  W = 2M 
W= 2*6
W = 12
Wesley was on vacation for 12 days. 

Let's double check our answer:
M + J + W = 21 days<span>6 + 3 + 12 = 21   
The numbers work out so the math is correct. Hope this helps and makes sense!</span>
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