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laila [671]
3 years ago
10

Eli wants to plant 45 sunflower plants, 81 corn plants and 63 tomato plants in his garden. If he put the same number of plants i

n each row and each row has only one type of plant, what is the greatest number of plants I can put in one row? Do I use GCF or LCM to solve this question?
Mathematics
1 answer:
Lynna [10]3 years ago
4 0

Answer:

9

Step-by-step explanation:

For this problem, you would use the GCF

Find the GCF of 45, 81, 63

GCF(45, 81, 63) = 9

45 = 9 * 5

81 = 9 *9

63= 9 * 7

Since 5, 9, 7 have no common factors, the GCF has to be 9.

This means that the greatest number of plants he can put in each row is 9.

The number of rows he uses for each plant will (obviously) vary.

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A family has three children.The oldest is 4 years older than the middle,and the youngest child is 2 years younger than the middl
lesantik [10]

Answer:

The age of the youngest child = x = 6 years

The age of middle child = y = 8 years

The age of the oldest child = z = 12 years

Step-by-step explanation:

Let us represent:

The age of the youngest child = x

The age of middle child = y

The age of the oldest child = z

The sum of the ages of the children is 26.

Hence: x + y + z = 26...... Equation 1

The oldest is 4 years older than the middle

z = 4 + y

The youngest child is 2 years younger than the middle child

x = y - 2

Hence, we substitute 4 + y for z and y - 2 for x in Equation 1

x + y + z = 26...... Equation 1

y - 2 + y + 4 + y = 26

y + y + y -2 +4 = 26

3y + 2 = 26

Subtract 2 from both sides

3y + 2 - 2 = 26 - 2

3y = 26 - 2

3y = 24

y = 24/3

y = 8

Solving for x

x = y - 2

x = 8 - 2

x = 6

Solving for z

z = 4 + y

z = 4 + 8

z = 12

Therefore:

The age of the youngest child = x = 6 years

The age of middle child = y = 8 years

The age of the oldest child = z = 12 years

7 0
3 years ago
Karen purchased a used vehicle that depreciates under a straight line method the initial value if the car is 4400 and the salvag
emmasim [6.3K]
It is expected to depreciate from 4400 to 800 in 6 years. The depreciation per year is the ratio
  depreciation per year = (total depreciation) / (number of years)

The total depreciation is the change in value, so the depreciation per year is
  (4400 - 800)/6 = 600

Karen expects the vehicle to depreciate by 600 each year.
4 0
3 years ago
Read 2 more answers
A senior class at Smith High School has 84 students.
sattari [20]

Answer: 44 boys and 40 girls

Step-by-step explanation:

x = number of girls

x + 4 = number of boys

x + x + 4 = 84

2x + 4 = 84

2x = 80

x = 40

84 - 40 = 44

3 0
3 years ago
I need someone to bullcr4p a couple of 200-word reports and ill give you 100 points each report
RideAnS [48]

Answer:

ok

Step-by-step explanation:

5 0
3 years ago
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Find the equation of the tangent line to the curve y = 2sinx at the point (pi/6,1). The equation of this tangent line can be wri
mixas84 [53]
Y = mx + b

1) m = slope of the tangent line = derivative at the point (pi/6, 1)

Function: y = 2sinx

Derivative: y ' = 2cosx

evaluate at x = pi/6=> y ' = 2cos(pi/6) = √3

2) equation using the slope and the point (pi/6, 1)

y - 1 = √3 ( x - pi/6 )

y = √3 x - √3(pi/6) +1 =√3 x + 0.093

y = √3 x + 0.093

m = √3, b = 0.093
8 0
4 years ago
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