Answer:
The function that models the total amount of money Julio has after weeks is:
f(x)=150+10x, where:
x is the number of weeks
Step-by-step explanation:
With the information provided, you can say that the total amount of money Julio has would be equal to the initial amount he has plus the result of multiplying the $10 that he saves every week for the number of weeks, which can be expressed as:
f(x)=150+10x, where:
x is the number of weeks
Marcus Garvey was <span>a Jamaican-American Civil Rights activist who was part of the "Back to Africa" movement of the early 20th century and founded the "Black Star Steamship Company" for this purpose.
He was also pro Pan-African movement which proposed the idea that all people of African descent should unite in order to improve the state of affairs in Africa. </span>
I would be glad to help you! I will solve through 3 to get you started.
This is a very important concept, so it would be helpful if you learn it on your own.
C= 2* pi* r
1. The radius is 5 cm. 5 cm represents r in the equation.
C= 2* 3.14 (or pi)* 5
Multiply it by using a calculator.
My answer was 31.4.
Let's try the second one.
2. The diameter is 9. Have of the diameter is the radius.
9/2= 4.5
Plug it into the equation.
C= 2*3.14*4.5
I got 28.26
One more.
Plug it into the equation.
C= 2*3.14*5.6
35.17 was my answer.
Make sure to add the end signs to you answer, ft, cm, meter, etc.
Let me know if you need more help.
Brainliest answer is always appreciated.
Answer:
y=x^3
Step-by-step explanation:
I don't know y sha
Answer:
the time taken for the radioactive element to decay to 1 g is 304.8 s.
Step-by-step explanation:
Given;
half-life of the given Dubnium = 34 s
initial mass of the given Dubnium, m₀ = 500 grams
final mass of the element, mf = 1 g
The time taken for the radioactive element to decay to its final mass is calculated as follows;
![1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} = (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500}) = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s](https://tex.z-dn.net/?f=1%20%3D%20500%20%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%20%5C%5C%5C%5C%5Cfrac%7B1%7D%7B500%7D%20%3D%20%20%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%5C%5C%5C%5Clog%28%5Cfrac%7B1%7D%7B500%7D%29%20%3D%20log%20%5B%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%5D%5C%5C%5C%5Clog%28%5Cfrac%7B1%7D%7B500%7D%29%20%20%3D%20%5Cfrac%7Bt%7D%7B34%7D%20log%280.5%29%5C%5C%5C%5C-2.699%20%3D%20%5Cfrac%7Bt%7D%7B34%7D%20%28-0.301%29%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7B2.699%20%5Ctimes%2034%7D%7B0.301%7D%20%5C%5C%5C%5Ct%20%3D%20304.8%20%5C%20s)
Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.
