1000 ways
First digit of codes: 10 choices (0-9)
Second digit of codes: 10 choices (0-9)
Third digit of codes: 10 choices (0-9)
10*10*10 = 1000
1. Yes, x=9 is a solution because 8x= 72, and 72 can be greater then and equal to 58.
2. 1 + 0.24j
3. 2 units
4. 25 students per classroom
Hope this helps!
Answer:
I would know if the table was included
Step-by-step explanation:
just insert the number of each type of movie into the place of M and see if it is greater than 15