1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iren [92.7K]
3 years ago
15

The probability of drawing an ace from a deck of cards is 1/13. If you drew one card at a time (and put the card back each time)

for 400 tries, how many times total could you expect to draw an ace
Mathematics
1 answer:
Digiron [165]3 years ago
4 0

Answer:

31 aces

Step-by-step explanation:

To find the number of aces you would expect, take the probability of an aces and multiply by the number of tries

1/13 * 400 =30.76923

Rounding up, approximately 31 aces

You might be interested in
FIRST PERSON TO ANSWER GETS BRAINLIEST!!!!!!!!!!!!
Fynjy0 [20]

Answer:D

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Help me with this questing plsss
docker41 [41]

Answer:

6.25n + 3.50

$34.75

Step-by-step explanation:

Break down the important information given in the problem.

The one-time delivery fee is 3.50. This is only paid one time an never again, making it the <u>constant</u>, a number that does not change.

Each lunch costs 6.25. This amount will increase depending on how many times Mr. Jackson orders lunches, "n" times. This number is the <u>rate</u> because it changes. The rate is attached to the variable.

If you add the amounts together, that is the total cost of ordering lunches.

6.25n + 3.50

(Reember expressions do not have the equal sign).

To find the cost of ordering 5 lunches, use the expression. Substitute "n" for 5 because "n" represents the number of lunches ordered.

6.25n + 3.50

= 6.25(5) + 3.50   Simplify by multiplying 5 and 6.25

= 31.25 + 3.50    Add the two values

= 34.75       Total cost of 5 lunches

Therefore the cost of ordering 5 lunches is $34.75.

8 0
3 years ago
the length of a varies string varies inversely as the frequency of its vibrations. A violin string 10 inches long vibrates at a
kolbaska11 [484]

Answer: <u><em>512</em></u>

Step-by-step explanation: <u><em>the length of a varies string varies inversely as the frequency of its vibrations. A violin string 10 inches long vibrates at a frequency of 512 cycles per second. Find the frequency of an 8-inch string.​</em></u>

<u><em /></u>

4 0
3 years ago
Read 2 more answers
Please help i will make brainliest
NARA [144]
It is answer b!!! hope this helps
5 0
3 years ago
Joey completed 3,556 push ups over a 4-week period (there are 7 days in a week). Joey did the same number of push-ups every day.
wel

Answer:

127 per day

Step-by-step explanation:

Total pushups in 4 weeks = 3,556

4-week period( 7 days a week) = 4 × 7

= 28 days

How many push-ups did Joey do each day?

Push ups per day = Total push ups / Total number of days

= 3,556 / 28

= 127

Push ups per day = 127

Joey did 127 push-ups each day for a 4-week period( 7 days a week)

6 0
3 years ago
Other questions:
  • Can two different integers have the same absolute value?
    13·2 answers
  • Please help. Which polynomial represents the quotient for the division problem shown?
    5·2 answers
  • Marquise has 200 meters of fencing to build a rectangular garden. The gardens area (in square meters) as a function of the garde
    9·1 answer
  • The graph below shows the total cost for lunch, c, when Will and his friends buy a large salad to share and several slices of pi
    8·2 answers
  • Which quadrilateral has no right angle
    11·2 answers
  • A business has a 200 ft wall and places 6 letters on the center of an exterior wall to spell sale. if there is 1 ft betweeen eac
    13·1 answer
  • Which point represents 2 1/4 on the graph
    6·2 answers
  • 1000 times 100 in exponent
    14·1 answer
  • Whats the answer to 5v - 42 - 73​
    9·1 answer
  • I’m not sure how to answer this pls help <br><br> 6.1 x 1.9 + 3.7
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!