What is the equation of a line that passes through (-2,-3) and is perpendicular to 2x-3y=6
1 answer:
For the perpendicular family we swap the coefficients on x and y, negating one. The point fixes the constant:
3x+2y = 3(-2)+2(-3)=-12
2y = -3x - 12
y = -3/2 x - 6
Choice A
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Y=-3x+4 is the correct answer
Answer:
when h(x) = 0, x = 7/3
Step-by-step explanation:
0 = 3x - 7
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7/3 = x
Is that considered two equations?
