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julia-pushkina [17]
3 years ago
13

The distance between Cincinnati, Ohio, and charlotte, North Carolina, is about 336 miles.The distance between Cincinnati and Chi

cago, Illinois, is about 247 miles. If Perry drove from charlotte to Chicago by way of Cincinnati, find the distance he drove.
Mathematics
1 answer:
Misha Larkins [42]3 years ago
4 0
<span>The distance of Cincinnati going to Charlotte, North CA = 336 miles
The distance of Cincinnati going to Chicago Illinois = 247 miles
Now, Let A = Charlotte, B = Cincinnati and C = Chicago. We assigned a variable to each places to make our illustration simple.
Perry, came from Charlotte, she’s going to Chicago via Cincinnati:
A ------------------------------------------------- B = 336 miles
B ------------------------------------------------- C = 247 miles
A ------------------------------------------------- C = (A-B) + (B-C)
=> 336 + 247
=> 583 miles.</span>



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Cosine law help! Really appreciate your guys hslp
Alexandra [31]
Answer: Either 25.0 or 25 depending on how your teacher wants you to format the answer

===========================================================

Explanation:

To start off, it probably helps to translate what the question wants. 
It states "For the pilot of airplane B, calculate the angle between the lines of sight to the airplane at C and Jenny's airplane [at point A]". 
This fairly long, and possibly complex, sentence boils down to "find angle B"

To find angle B, we need to find the length of side 'a' first

Let,
a = x
b = 4.2
c = 5.7

Note how the lowercase letters (a,b,c) are opposite their uppercase counterparts (A,B,C). This is often the conventional way to label triangles. The lowercase letters are usually for the side lengths while the upper case is for the angles.

We have angle A = 120 degrees

Plug these values into the law of cosines formula below. Then solve for x
a^2 = b^2 + c^2 - 2*b*c*cos(A)
x^2 = 4.2^2 + 5.7^2 - 2*4.2*5.7*cos(120)
x^2 = 17.64 + 32.49 - 47.88*cos(120)
x^2 = 17.64 + 32.49 - 47.88*(-0.5)
x^2 = 17.64 + 32.49 + 23.94
x^2 = 74.07
x = sqrt(74.07)
x = 8.60639297266863
x = 8.6064

So side 'a' is roughly 8.6064 kilometers when we round to four decimal places

Now we'll use this to find angle B
Use the law of cosines again, but this time, the formula is slightly altered so that angle B is the focus instead of angle A

Plug in the side lengths (a,b,c). Solve for angle B
b^2 = a^2 + c^2 - 2*a*c*cos(B)
(4.2)^2 = (8.6064)^2 + (5.7)^2 - 2*(8.6064)*(5.7)*cos(B)
17.64 = 74.07012096 + 32.49 - 98.11296*cos(B)
17.64 = 106.56012096 - 98.11296*cos(B)
17.64 - 106.56012096 = 106.56012096 - 98.11296*cos(B)-106.56012096
-88.92012096  = -98.11296*cos(B)
(-88.92012096)/(-98.11296)  = (-98.11296*cos(B))/(-98.11296)
0.906303519535034 = cos(B)
cos(B) = 0.906303519535034
arccos(cos(B)) = arccos(0.906303519535034)
B = 25.0005785532867

It's a bit messier this time around, but we get the approximate angle
B = 25.0005785532867
which rounds to
B = 25.0 degrees
when we round to the nearest tenth. We can write "25.0" as simply "25"

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s= 180° x 4

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now since in a regular shape, each interior angle is equal. We just divide the total interior angle with a number of sides

6.

720° divided by 6 is equal to 120°

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Use properties of exponents to write an equivalent expression
Nataly_w [17]

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Step-by-step explanation:

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