Answer:
D
Step-by-step explanation:
its just obvious
go bucs
Answer:
b
Step-by-step explanation:
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
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now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
John made $40 commissions for $500 sales or 40/500. He wants $320 for an unknown amount of sales or 320/x.
40/500=320/x Cross multiply.
40x=160,000
Divide both sides by 40.
X=4,000
He needs his sales to be $4,000 to get $320 in commission.
X²+y² =(Radius)²
x²+y² =10². So the radius is 10