Hello :
<span>f(x)=x²+4x-5
</span><span>The axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2 :
</span>f(x) = (x+2)² + b
f(x) x²+4x+4+b= x² +4x-5
4+b= -5
b = -9
the vertex is : (2 , -9)
Answer:
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Step-by-step explanation:
these are all irrational! hope this helped you :3.
Y=-5x-7. I'm almost certain but you never know
Hi! Your answer is q = -9
Please see an explanation for a better and clear understanding to your problem.
Any questions about my answer and explanation can be asked through comments! :)
Step-by-step explanation:
Since we want to solve for q-term. That means we are going to isolate q-term.

We can add 4 and 9 together.

Because we want to know the value of q. That means we have to isolate q-term by subtracting both sides by 13.

We are reaching to the final step where we divide the whole equation by 3.

Finally, the solution for this equation is q = -9. But what if you are not certain or sure about the answer? Let's check it out!
To check the answer, simply substitute q = -9 in the equation.

Notice that the equation is true for q = -9. Hence, we can conclude that the solution for this equation is q = -9.
Hope this helps!
The rule to find the term is: y=225-4x
you want to know the 82nd term which occurs when x=82 therefore
y = 225-(4 x 82) = -103
82nd term = -103