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Bess [88]
3 years ago
5

Identify the surface with the given vector equation. r(u, v) = 2 sin(u) i + 5 cos(u) j + v k, 0 ≤ v ≤ 5 plane hyperbolic parabol

oid circular paraboloid elliptic cylinder circular cylinder
Mathematics
1 answer:
olchik [2.2K]3 years ago
6 0
Note that this just produces three parametric equations:

x(u) = 2 \sin(u)
y(u) = 5 \cos(u)
z(v) = v

In the x-y plane, this is just he parametric equation for an ellipse (as a function of u). The z is simply a linear function. 

The surface is then an ellipse extruded along the z-axis. We get a elliptic cylinder.
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PLEASE! WILL GIVE METAL AND FAN.
Pani-rosa [81]
20000*0.45 = 9000 in the bond
20000*0.15 = 3000 in the CD
20000*0.20 = 4000 in stocks
20000*0.029 = 580 in savings

A=9000(1 + 4.35%)^3 = 10,226.33
A=3000(1 + 2.90%)^3 = 3,268.64
A=4000 (1 + 8%) x (1 - 4%) x (1 + 6%) = 4,396.03
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Gain = 22,436.04 - 20,000 = 2,436.04
6 0
3 years ago
Read 2 more answers
If the endpoints of the diameter of a circle are (9, 4) and (5, 2), what is the standard form equation of the circle?
sattari [20]
The standard forrm equation of the circle is (x-h)² + (y-k)² = r²
where h,k : x,y-coordinate of the center
           r : radius of the circle
Get the center of the circle : h = (x1 + x2)/2 = (9+5)/2 = 7
                                             k = (y1 + y2)/2 = (4+2)/2 = 3
=> the center is (7,3)
Because the given information gave 2 endpoints so we can choose one of these, then use the distance formula to get the radius
                                            r = √(x1 - h)² + (y1 - k)²
                                            r = √(9 - 7)² + (4 - 3)²
                                            r = √2² + 1² 
                                            r = √5
Finally, the equation of the circle is (x - 7)² + (y - 3)² = (√5)²
                                                        (x - 7)² + (y - 3)² = 5
4 0
4 years ago
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gtnhenbr [62]
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Answer:

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