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2 years ago

Plssss HELP MEEEEEE i shall give thanks

Mathematics

2 answers:

vagabundo [1.1K]2 years ago

7 0

Answer:

youre welcome

Step-by-step explanation:

brilliants [131]2 years ago

5 0

Hope this helps you

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45/200 x + x = 3920 what does x equal?

blagie [28]

Answer:

3/52528

Step-by-step explanation:

4 0

3 years ago

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What is 75 percent in fraction and decimal

k0ka [10]

75% in fraction is 3/4 and the decimal is 0.75

4 0

3 years ago

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If £21 = 500 rubles, how many £ are in 780 rubles? Give your answer to 2 dp

Aleksandr [31]

Answer:

£32.76

Step-by-step explanation:

21/500=0.042

780x0.042 = 32.76

5 0

2 years ago

Someone please help me out please!!!!

Tom [10]

Given:

A committee of 6 members is to be chose from the 100 members of the U.S. senate.

To find:

The number of ways to form a committee.

Solution:

We have,

Total number of members = 100

Number of members needs to selected of committee = 6

Number of ways to select r items from total n items is

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Number of ways to select 6 members from total 100 members is

$^{100}C_6=\dfrac{100!}{6!(100-6)!}$

$^{100}C_6=\dfrac{100\times 99\times 98\times 97\times 96\times 95\times 94!}{6\times 5\times 4\times 3\times 2\times 1\times 94!}$

$^{100}C_6=\dfrac{100\times 99\times 98\times 97\times 96\times 95}{6\times 5\times 4\times 3\times 2\times 1}$

$^{100}C_6=1192052400$

Therefore, the total number of ways to form a committee is $^{100}C_6$ , i.e., equal to $1192052400$ .

4 0

3 years ago

Integrate sin^-1(x) dx please explain how to do it aswell ...?

Lynna [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2264253

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx\qquad\quad\checkmark}$

Trigonometric substitution:

$\mathsf{\theta=sin^{-1}(x)\qquad\qquad\dfrac{\pi}{2}\le \theta\le \dfrac{\pi}{2}}$

then,

$\begin{array}{lcl} \mathsf{x=sin\,\theta}&\quad\Rightarrow\quad&\mathsf{dx=cos\,\theta\,d\theta\qquad\checkmark}\\\\\\ &&\mathsf{x^2=sin^2\,\theta}\\\\ &&\mathsf{x^2=1-cos^2\,\theta}\\\\ &&\mathsf{cos^2\,\theta=1-x^2}\\\\ &&\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\checkmark}\\\\\\ &&\textsf{because }\mathsf{cos\,\theta}\textsf{ is positive for }\mathsf{\theta\in \left[\dfrac{\pi}{2},\,\dfrac{\pi}{2}\right].} \end{array}$

So the integral $\mathsf{(ii)}$ becomes

$\mathsf{=\displaystyle\int\! \theta\,cos\,\theta\,d\theta\qquad\quad(ii)}$

Integrate $\mathsf{(ii)}$ by parts:

$\begin{array}{lcl} \mathsf{u=\theta}&\quad\Rightarrow\quad&\mathsf{du=d\theta}\\\\ \mathsf{dv=cos\,\theta\,d\theta}&\quad\Leftarrow\quad&\mathsf{v=sin\,\theta} \end{array}\\\\\\\\ \mathsf{\displaystyle\int\!u\,dv=u\cdot v-\int\!v\,du}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-\int\!sin\,\theta\,d\theta}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-(-cos\,\theta)+C}$

$\mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta+cos\,\theta+C}$

Substitute back for the variable x, and you get

$\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=sin^{-1}(x)\cdot x+\sqrt{1-x^2}+C}\\\\\\\\ \therefore~~\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=x\cdot\,sin^{-1}(x)+\sqrt{1-x^2}+C\qquad\quad\checkmark}$

I hope this helps. =)

Tags: integral inverse sine function angle arcsin sine sin trigonometric trig substitution differential integral calculus

6 0

3 years ago