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Mrac [35]
3 years ago
6

WHUR Radio uses 1/5 of its of its 10 hours of daytime broadcast for commercial and 1/2 for music. How much is left for news?

Mathematics
1 answer:
Nataly [62]3 years ago
8 0

Answer: 3 hours

Step-by-step explanation:

From the question, we are informed that WHUR Radio uses 1/5 of its of its 10 hours of daytime broadcast for commercial and 1/2 for music.

Hours used for commercial:

= 1/5 × 10

= 2 hours

Hours used for music:

= 1/2 × 10

= 5 hours

Hours left for news will be:

= 10 hours - 2 hours - 5 hours

= 3 hours

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In the complex number 4 + 2i, 4 is the <em>real </em>part. In the complex number 4 + 2i, 2 is the <em>imaginary </em>part.

Step-by-step explanation:

The two parts of the complex number are called the <em>real</em> part and the <em>imaginary</em> part. The imaginary part is identified by its multiplier of <em>i</em>.

In the given number, the 2 is multiplied by i, so 2 is the imaginary part. The other part, 4, is the real part.

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David’s bank offers a 36-month Certificate of Deposit (CD) with an APR of 2.25%. Use the compound interest formula to answer the
tamaranim1 [39]

Using compound interest, it is found that:

a) A(8) = 2389.66

b) t = 31.15

c) P = 1870.85

Compound interest:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

  • A(t) is the amount of money after t years.  
  • P is the principal(the initial sum of money).  
  • r is the interest rate(as a decimal value).  
  • n is the number of times that interest is compounded per year.  
  • t is the time in years for which the money is invested or borrowed.

In this problem:

  • The APR is of 2.25%, hence r = 0.0225.
  • No information about the number of compounding per year, hence n = 1.

Item a:

P = 2000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

A(8) = 2000\left(1 + \frac{0.0225}{1}\right)^{8}

A(8) = 2389.66

Item b:

A(t) = 4000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

4000 = 2000\left(1 + \frac{0.0225}{1}\right)^{t}

(1.0225)^t = 2

\log{(1.0225)^t} = \log{2}

t\log{1.0225} = \log{2}

t = \frac{\log{2}}{\log{1.0225}}

t = 31.15

Item c:

A(3) = 2000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

2000 = P\left(1 + \frac{0.0225}{1}\right)^{3}

P = \frac{2000}{(1.0225)^3}

P = 1870.85

A similar problem is given at brainly.com/question/24850750

7 0
2 years ago
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