Let A represent the amount Ann contributed, Z represent Zoe's contribution, and J represent Jim's contribution toward the present.
Ann (A): A
Zoe (Z): A = Z - 12 → Z = 12 + A
Jim (J): A = J - 16 → J = 16 + A
A + Z + J = 154
(A) + (12 + A) + (16 + A) = 154
3A + 28 = 154
3A = 126
A = 42
Ann (A): A = 42
Zoe (Z): Z = 12 + A = 12 + 42 = 54
Jim (J): J = 16 + A = 16 + 42 = 58
Answer: Ann=42, Zoe=54, Jim=58
Answer:
first top left graph? 12×4 is 48 so that puts it about right
Answer:
Subtract two from 8, the remainder is x. In this case, it is 6.
For future questions, try to think of x as a mystery number rather than a letter. You got this. :)
Answer:
<u>Question 9</u>
Name the ordered pairs in the table: 3, 4, 5, 6, 7
Ordered pairs: (1,3), (2,4), (3,5), (4,6), (5,7)
Graph the equation: the attachment
Step-by-step explanation:
I don't know how to do questions 11 and 12.
Also sorry if these aren't correct.
It could be PEMDAS.
That means solve by this order:
1). Parenthesis
2). Exponents
3). Multiplication
4). Division
5). Addition
6). Subtraction
To remember the order they say it like
this " Please Excuse My Dear Aunt Sally "