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Mice21 [21]
3 years ago
8

Use the graph of y = ex to evaluate the expression e0.

Mathematics
2 answers:
notsponge [240]3 years ago
7 0
A screenshot of the graph is attached.

When x=0, the value of y=eˣ is 1.

This is shown on the graph.

Zina [86]3 years ago
4 0

Answer:

the answer is b on edg

Step-by-step explanation:

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5.
Kryger [21]

Answer:

D. Yes, since the slopes are the same and the y-intercepts are different.

Step-by-step explanation:

yes because both line have a slope of .857/2

...................................................................................................................................................

yes; both have a slope of 3/7

...................................................................................................................................................

Yes. They have the same slope.

8 0
2 years ago
ducational Television In a random sample of people, said that they watched educational television. Find the confidence interval
SIZIF [17.4K]

Complete Question

Educational Television In a random sample of 200 people, 159 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.

Answer:

The 90% confidence interval is   0.748  <  p <  0.842      

Step-by-step explanation:

From the question we are told that

     The sample size is  n = 200

     The number of people that watched the educational television is k =  159

Generally the sample proportion is mathematically represented as

               \^ p =  \frac{159}{200}

=>               \^ p =  0.795

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>     E =  1.645  * \sqrt{\frac{0.795 (1- 0.795)}{200} }

=>     E = 0.04696

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.795  -0.04696  <  p <  0.795 + 0.04696

=>    0.748  <  p <  0.842      

3 0
3 years ago
The identifying letter at the top of a column is called the
Papessa [141]
Can you give more information on your question? 
8 0
3 years ago
Select the exclusion that fits best with this problem.<br><br><br><br> 13x^6/51x^4
Damm [24]

ANSWER

x \ne0

EXPLANATION

The given problem is

\frac{13 {x}^{6} }{ 51 {x}^{4}  }

This is defined if and only if

x \ne0

Even the given expression can be simplified to obtain:

\frac{13 {x}^{2} }{ 51}

The exclusion is

x \ne0

5 0
3 years ago
Plz someone help me on this too plz plz
san4es73 [151]
1. 7 and -7 are both 7 units away from 0.  They are 14 units away from each other. Absolute value helps because rather than 7+(-7) being 0 absolute value makes anything positive so it becomes 7+7=14 to be able to count the units between the two.

2. 5 and -5 are both 5 units away from 0.  They are 10 units away from each other. Absolute value helps because rather than 5+(-5) being 0 absolute value makes anything positive so it becomes 5+5=10 to be able to count the units between the two.

3. 2 and -2 are both 2 units away from 0.  They are 4 units away from each other. Absolute value helps because rather than 2+(-2) being 0 absolute value makes anything positive so it becomes 2+2=4 to be able to count the units between the two.

Hope that helps
8 0
3 years ago
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