All categories

3 years ago

What is the solution of the equation 8(3x + 4) = 2(12x − 8)?

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

8(3x + 4) = 2(12x − 8)

Open brackets

24x + 32 = 24x - 16

Collecting like terms

24x - 24x = -16 - 32

No Solution since the x as cancelled out

You might be interested in

Help will give Brainly points

Eduardwww [97]

D is the right answer

6 0

2 years ago

Read 2 more answers

ASAP PLEASE GIVE CORRECT ANSWER

Step2247 [10]

distance of a point $(x,y)$ from origin is $\sqrt{x^2+y^2}$

so distance is $\sqrt{(-15)^2+(8)^2}=\sqrt{225+64}=\sqrt{289}=17$

4 0

3 years ago

Read 2 more answers

If y=x^2+kx-k for what values of k will the quadratic have 2 real solutions

xeze [42]

The key to answering this question lies in finding the discriminant b^2-4ac. If b^2-4ac is greater than zero, the quadratic equation will have 2 real solutions.

Typing out y=x^2+kx-k, we see that a=1, b=k and c = -k. The discriminant in this case is

b^2 - 4(a)(c), or k^2 - 4(1)(-k), or k^2 + 4k

For which k is this k^2 + 4k = 0? Factor k^2 + 4k, obtaining k(k+4) = 0; the roots of this are k=0 and k = -4.

Now set up a number line for k, drawing empty circles at k = 0 and k = -4. These two values divide the number line into three intervals:

(-infinity, -4), (-4, 0) and (0, infinity). Choose a test number for each interval:

-6 for the first, -2 for the second and 4 for the third. Determine whether k^2 + 4k > 0 for any of these test numbers:

(-6)^2 + 4(-6) = 36 - 24 = +12. Yes, the discriminant is + on the interval (-infinity, -4)

(-2)^2 + 4(-2) = 4 - 8 = -4. No, the discriminant is not + on (-4, 0).

(4)^2 + 4(4) = 32. Yes, the discrim. is + on (0, infinity).

So: The given quadratic will have two different, real roots on the two intervals (-infinity, -4) and (0, infinity).

4 0

3 years ago

A textile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean thread elongation of 12 ki

MakcuM [25]

Answer:

P-value = 0.02275

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 12 kilograms

Sample mean, $\bar{x}$ = 11.5 kilograms

Sample size, n = 4

Alpha, α = 0.05

Population standard deviation, σ = 0.5 kilograms

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 12\\H_A: \mu < 12$

We use one-tailed(left) z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{11.5 - 12}{\frac{0.5}{\sqrt{4}} } = -2$

We calculate the p-value from the standard z-table:

P-value = 0.02275

5 0

3 years ago

A system of two linear equations has no solution. One equation is 3x – 6y = 5. Select the equation that would make this system h

liq [111]

Answer:

d is the answer

Step-by-step explanation:

6 0

3 years ago