Answer:
Hi the answer is =
Step-by-step explanation:
Because 'w' isn't really an exact number so w/2 would become 2, therefore it is equal.
Hope this helped! > ‿ <
Same Denominator We Add The Numerators:
Answer:
It would be 1 copy, and would cost $42.
39+3(1)=42$
30+12(1)=42$
39+3x, 30+12x are the equations
Answer:
Strictly speaking, there is not enough information to solve the problem.
If we assume m<EFY = 90, then:
m<DEY = 29
m<DEF = 58
Step-by-step explanation:
Going by the exact information shown, the answer is really that there isn't enough information to answer the question.
On the other hand, if angle EFY is a right angle, then we have two right triangles that can be proved congruent by HL. Then by CPCTC, angles DEY and FEY are congruent. We set their measures equal and solve for y.
4y - 7 = 2y + 11
2y = 18
y = 9
m<DEY = 4y - 7 = 4(9) - 7 = 36 - 7 = 29
m<DEF = 2m<DEY = 2(29) = 58
Answer:
8568 ways
Step-by-step explanation:
We have to in this particular case the order to find a 5 person group out of a class of 18, when order does not matter, we use combinations. In this case n = 18 and r = 5.
We have that the combination formula is:
nCr = n! / (r! * (n-r)!)
replacing we have:
18C5 = 18! / (5! * (18-5)!)
18C5 = 8568
What it means in total are 8568 ways of arms groups.