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Jobisdone [24]
3 years ago
6

Nine students ask to visit a college admissions counselor. Each scheduled visit includes one student. In how many ways can they

be scheduled??
Mathematics
2 answers:
rjkz [21]3 years ago
6 0
When you have to count in how many ways you can arrange something, you need permutations: you have 9 possible students to schedule as first, the second visit will be scheduled with one of the remaining 8 students, the third one with one of the remaining 7 students, and so on until the last one, therefore:

9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 362880

The students can be scheduled in 362880 ways.
ElenaW [278]3 years ago
5 0

There are n! ways to order n objects.

So, the answer is 9!=362,880 ways.

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A proper fraction is converted to a decimal equivalent by dividing the denominator into the numerator. True
kondaur [170]

False, it's the other way around: you divide the numerator by the denominator.

For example, to evaluate \frac{8}{15} you divide 8 by 15:

\dfrac{8}{15} = 8\div 15 = 0.5\overline{3}

7 0
3 years ago
after spending 7/9 of a three hours examination, a student left the exams hall. How many minutes has he to complete the duration
Montano1993 [528]
40 mins left! total time= 60 mins x 3 hours =180 mins. 180 divided by 9 is 20. 20 times 7 is 140. 180-140 equals 40. yay!
6 0
2 years ago
I really need help with this problem please help
VLD [36.1K]
I think the answer is going to be a

7 0
3 years ago
M Find the measure of the angles.
bearhunter [10]

Answer:

Since the interior angles of a triangle add up to be 180 degrees, I set up the equation like so:

x + 59 + x + 51 + 84 = 180 My equation

2x + 194 = 180 add like terms

2x = -19 subtract 194 from both sides of the equation

x = -7 divided both by 2x to get x alone

It has occurred to me that I am finding x here (it still makes no sense to get a negative number) but this is the only equation I know to set up.

Notes:

This is for geometry homework and I realize just asking you to solve my problems is academically dishonest off topic if I have not put genuine effort into the question, which I have (put effort in, that is). I have put a lot of mental effort into figuring this out, though, so I will tell you what I did and hopefully you can tell me where I went wrong and how to correct my mistake, because I think it is obvious I made one. For the record I accidentally deleted my math notes from my iPad and Googling the question this morning produces hard to understand results. My geometry teacher was unavailable while I was working last night due to my lack of internet connection.

6 0
2 years ago
A sample of 66 obese adults was put on a low-carb diet for a year. The average weight loss was 11 pounds and the standard deviat
Illusion [34]

Answer:

The 99% lower confidence bound for the true average weight loss is 3.98 pounds.

This means that we can be 99% sure that the mean weight loss for all obese adults on a low-carb diet is positive.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575*\frac{19}{\sqrt{66}} = 6.02

The lower end of the interval is the sample mean subtracted by M. So it is 11 - 6.02 = 3.98 pounds

The 99% lower confidence bound for the true average weight loss is 3.98 pounds.

This means that we can be 99% sure that the mean weight loss for all obese adults on a low-carb diet is positive.

7 0
2 years ago
Read 2 more answers
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