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NARA [144]
3 years ago
8

How are the decimals 0.5 0.05 and 0.005 related

Mathematics
1 answer:
Ilya [14]3 years ago
4 0
They are either in the tenths place, the hundredths place, or the thousandths place. Multiplying 0.5 by 0.1 will get you 0.05, and multiplying 0.05 by 0.1 will get you 0.005.
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a meteorologist measures the angle of elevation of a weather balloon with the ground as 41. A radio signal from the balloon indi
Aneli [31]
Here you would use right triangle trig (SOH CAH TOA)
So first draw a right triangle. Imagine youre standing at the angle opposite the right angle which is the one on the ground.This angle is the 41°. Now Imagine the balloon is as the angle above the right triangle. Well since the balloon is 1503 m from his location this would be the hypotenuse. SInce we are trying to find the height (x) we would use sine since
sine = opposite/hypotenuse . Now lets solve make sure calculator is in degree mode:

sin41 = x/1503      multiply both sides by 1503 to cancel it out
1503sin41 = x        plug into calculator
x = 986.057 ft
The balloon is 986.057 feet above the ground.


6 0
3 years ago
Read 2 more answers
I would like to know the right answer of this graph.
jeka94

Answer:

(6,-4)

Step-by-step explanation:

P(-2,2)

-2 - 4 = 6

2 - 6 = -4

4 0
3 years ago
Select the quadratic function that corresponds to each graph below
ozzi
C B A are the orders of the answers
5 0
3 years ago
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What is the definition of intersection In math?
miskamm [114]

Answer:

Step-by-step explanation:

an intersection is a point, line, or curve common to two or more objects

6 0
3 years ago
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The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth
Art [367]

Answer:

a) N_0=250\; k=0.15

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies t=0. And N(0)=N_0. The process is:

N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250

b) After 2 days means t=48. So, we just replace and operate:

N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}

c) N(t_1)=4000; \;t_1=?

N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\  \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h

d) t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)

N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h

6 0
3 years ago
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