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Alja [10]
3 years ago
9

Jala put $600 in an interest bearing account with a annual compound interest rate of 5%. Jala determined that after seven years,

she will have a total balance of $844.26. Using the rule of 72, mc010-1.jpg how many more years will it be before Jala’s $600 doubles in value? Round to the nearest tenth.
Mathematics
2 answers:
makkiz [27]3 years ago
5 0
14 years is the correct anwser


Rufina [12.5K]3 years ago
3 0
14 years. Would be your answer.


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I don’t know how to do this HELP
mafiozo [28]

Answer:

Both

Step-by-step explanation:

5+3+4=

12

3+1+1=

5

1+1=

2

1=

1

The line plot shows this data for each number.

4 0
2 years ago
Find the value of expression:15/3+(7-3)^2
irina1246 [14]

Answer:

21

Step-by-step explanation:

5 0
3 years ago
In a sprint to the finish, a professional cyclist travels 380 meters in 20 seconds. At that rate, how many meters will the cycli
lutik1710 [3]

Answer:

133m

Step-by-step explanation:

Rate can be defined as the measure of a quantity with time

Rate the professional cyclist travels =380/20

To know the rate rate, in meters will the cyclist travel in 7 seconds then we equate the rate above as

380/20= x/7

Cross multiply

380×7=20X

2660= 20x

X=133m

Hence, the rate rate, in meters will the cyclist travel in 7 seconds is 133m

5 0
3 years ago
The half-life of the radioactive element unobtanium-43 is 10 seconds. If 48 grams of unobtanium-43 are initially present, how ma
natka813 [3]

Answer:

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

Step-by-step explanation:

Given;

initial mass of the radioactive element  = 48 grams

half life, t = 10 seconds

time of decay (s)                          remaining mass of the  radioactive element

0 ------------------------------------------------- 48 grams

10------------------------------------------------- 24 grams

20 ------------------------------------------------- 12 grams

30 -------------------------------------------------- 6 grams

40 --------------------------------------------------- 3 grams

50 ----------------------------------------------------- 1.5 grams

60------------------------------------------------------0.75 grams

Thus;

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

7 0
3 years ago
Find smallest number which on adding to 19 it is exactly divisible by 28,36 and 45 (LCM).
BabaBlast [244]

Answer:

1241

Step-by-step explanation:

∴

L.C.M. of 28, 36 and 45 = 2 × 2 × 3 × 3 × 5 × 7 = 1260

∴

the required number is 1260 - 19 = 1241

Hence, if we add 19 to 1241 we will get 1260 which is exactly divisible by 28, 36 and 45.

7 0
1 year ago
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