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3 years ago

10

How to read a inch ruler

2 answers:

xxTIMURxx [149]3 years ago

5 0

Answer: I am not sure how to answer this question besides the fact a inch ruler will have 12 inches. 12 inches equal 1 foot. Each foot is broken down into inches. Hope this helps :)

Step-by-step explanation:

andrezito [222]3 years ago

3 0

Answer: there are 2 sides to a ruler. But your question asked for a inch ruler. All 12 inches are broken down in small pieces and make a (1) foot. Hope this helps you understand better... :)

Step-by-step explanation:

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Paul had some candy to give his five children. He first took ten pieces for himself and then evenly divided the rest among his c

nikitadnepr [17]

Answer:

25 pieces

Step-by-step explanation:

let c = amt of candy

(c - 10 ) / 5 = 3

cross-multiply:

c-10 = 15

c = 25

3 0

3 years ago

The following results come from two independent random samples taken of two populations.

photoshop1234 [79]

Answer:

$(a)\ \bar x_1 - \bar x_2 = 2.0$

$(b)\ CI =(1.0542,2.9458)$

$(c)\ CI = (0.8730,2.1270)$

Step-by-step explanation:

Given

$n_1 = 60$ $n_2 = 35$

$\bar x_1 = 13.6$ $\bar x_2 = 11.6$

$\sigma_1 = 2.1$ $\sigma_2 = 3$

Solving (a): Point estimate of difference of mean

This is calculated as: $\bar x_1 - \bar x_2$

$\bar x_1 - \bar x_2 = 13.6 - 11.6$

$\bar x_1 - \bar x_2 = 2.0$

Solving (b): 90% confidence interval

We have:

$c = 90\%$

$c = 0.90$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.90$

$\alpha = 0.10$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.10/2}$

$z_{\alpha/2} = z_{0.05}$

The z score is:

$z_{\alpha/2} = z_{0.05} =1.645$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.645 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.645 * \sqrt{0.3306}$

$2.0 \± 0.9458$

Split

$(2.0 - 0.9458) \to (2.0 + 0.9458)$

$(1.0542) \to (2.9458)$

Hence, the 90% confidence interval is:

$CI =(1.0542,2.9458)$

Solving (c): 95% confidence interval

We have:

$c = 95\%$

$c = 0.95$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.95$

$\alpha = 0.05$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.05/2}$

$z_{\alpha/2} = z_{0.025}$

The z score is:

$z_{\alpha/2} = z_{0.025} =1.96$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.96 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.96* \sqrt{0.3306}$

$2.0 \± 1.1270$

Split

$(2.0 - 1.1270) \to (2.0 + 1.1270)$

$(0.8730) \to (2.1270)$

Hence, the 95% confidence interval is:

$CI = (0.8730,2.1270)$

8 0

3 years ago

Choose the graph of the solution to this inequality.

Dmitriy789 [7]

Answer:

we can translate the given statement into-8 ≥ -5x + 2 > -38.

In this case, we can dissect the inequality into two parts:

-8 ≥ -5x + 2 and -5x + 2 > -38

Step-by-step explanation:

-8 ≥ -5x + 2 5x ≥ 10x ≥ 2 (closed dot)

-5x + 2 > -38 5x < 40x < 8 (open dot)

The answer then is c) number line with a closed dot on 2 and an open dot on 8 and shading in between

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2 years ago

A piece of machinery depreciates 6000 the first year 5500 the second year and 5000 the third year. If the rate of depreciation i

podryga [215]

Answer:

3500

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3 years ago

What’s the slope of (8,4) and (6,5)

Volgvan

Answer: A positive slope

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3 years ago

Read 2 more answers