The sequence is, in fact, quadratic. It is described by the equation
.. a[n] = (n*(n -1))/2 +2
First differences are increasing, so the sequence will not be arithmetic. An arithmetic sequence has constant first differences.
Second differences are constant, so the sequence will not be geometric. A geometric sequence will have first-, second-, third-differences, and those to any level, that have the same constant ratio as the terms of the original sequence.
Answer:
-2a^4+8a^3-6a^2
Step-by-step explanation:
2a^2(a-1)(3-a)
2a^2(-a^2 +3a-3+a)
2a^2(-a^2+4a-3)
-2a^4+8a^3-6a^2
Answer:
Pr(X >42) = Pr( Z > -2.344)
= Pr( Z< 2.344) = 0.9905
Step-by-step explanation:
The scenario presented can be modeled by a binomial model;
The probability of success is, p = 0.65
There are n = 80 independent trials
Let X denote the number of drivers that wear a seat belt, then we are to find the probability that X is greater than 42;
Pr(X > 42)
In this case we can use the normal approximation to the binomial model;
mu = n*p = 80(0.65) = 52
sigma^2 = n*p*(1-p) = 18.2
Pr(X >42) = Pr( Z > -2.344)
= Pr( Z< 2.344) = 0.9905
Answer:
8n^2+10n-25
Step-by-step explanation:
it's probably wrong that's what I got tough xp
Answer:
Step-by-step explanation:
