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3 years ago

Find the measure of the complement of a 7979degrees° angle.

2 answers:

7 0

Hello :
<span>7979 °=360°× 22 + 59°
</span><span> the complement of a 7979degrees° is : x
x+</span>59°=180°
x= 180°-59° =121°

lutik1710 [3]3 years ago

3 0

Answer:

31⁰

Step-by-step explanation:

7979 = 360 × 22 + 59

Complemebt = 90 - 59 = 31⁰

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Find the minimum and maximum possible areas for a rectangle measuring 4.15 cm by 7.34 cm. Round to the nearest hundredth. A. min

Shalnov [3]

This is probably in the context of a discussion of significant figures and accuracy.

When we record a measurement of 4.15 cm with two significant figures, that means we believe the exact value is in the range from 4.145 cm to 41.155 cm

Similarly 7.34 really means between 7.335 and 7.345 cm.

The minimum area rectangle is

$4.145 \times 7.335 = 30.403575 \approx 30.40$

The maximum area rectangle is

$4.155 \times 7.345 =30.518475 \approx 30.52$

Choice A

5 0

3 years ago

Read 2 more answers

For which values of the parameter B the following system admits a unique solution [ 1 b 1-b 2 2 0 2–2B 4 0] [x y z] = [1 2 0]

photoshop1234 [79]

Answer: β ≠ ±1

Step-by-step explanation: For a system of equations to have an unique solution, its determinant must be different from 0: det |A| ≠ 0. So,

det $\left[\begin{array}{ccc}1&\beta&1-\beta\\2&2&0\\2-2\beta&4&0\end{array}\right]$ ≠ 0

Determinant of a 3x3 matrix is calculated by:

det $\left[\begin{array}{ccc}1&\beta&1-\beta\\2&2&0\\2-2\beta&4&0\end{array}\right]\left[\begin{array}{ccc}1&\beta\\2&2\\2-2\beta&4\end{array}\right]$

$8(1-\beta)-[2(2-2\beta)(1-\beta)]$

$8-8\beta-4+8\beta-4\beta^{2}$

$-4\beta^{2}+4\neq 0$

$\beta^{2}\neq 1$

$\beta \neq \sqrt{1}$

β ≠ ±1

For the system to have only one solution, β ≠ 1 or β ≠ -1.

7 0

3 years ago

Find the measure of each of the angles. Don’t forget to label your answer

user100 [1]

Answer:

$a=125^o$

$b=55^o$

$c=55^o$

$d=55^o$

$e=125^o$

$f=55^o$

Step-by-step explanation:

step 1

Find the value of x

we know that

$(2x+25)^o=(x+75)^o$ ----> by alternate interior angles

solve for x

Group terms

$2x-x=75-25$

$x=50$

step 2

Find the measure of angle a

we know that

$a=(x+75)^o$ ----> by vertical angles

substitute the value of x

$a=(50+75)=125^o$

step 3

Find the measure of angle b

we know that

$a+b=180^o$ ----> by supplementary angles (form a linear pair)

we have

$a=125^o$

substitute

$125^o+b=180^o$

$b=180^o-125^o=55^o$

step 4

Find the measure of angle c

we know that

$c=b$ ----> by vertical angles

we have

$b=55^o$

therefore

$c=55^o$

step 5

Find the measure of angle d

we know that

$d=b$ ----> by corresponding angles

we have

$b=55^o$

therefore

$d=55^o$

step 6

Find the measure of angle e

we know that

$e=a$ ----> by alternate exterior angles

we have

$a=125^o$

therefore

$e=125^o$

step 7

Find the measure of angle f

we know that

$f=d$ ----> by vertical angles

we have

$d=55^o$

therefore

$f=55^o$

4 0

3 years ago

The center on a target has a diameter of 5 inches. The whole target has a diameter of 25 inches. Complete the explanation for wh

kicyunya [14]

Answer:

The center is $\frac{1}{25}$ of the whole target.

Step-by-step explanation:

Given:

Diameter of the center = 5 inches

Diameter of the whole target = 25 inches

We need to find the part of the center to the whole target.

Solution,

Firstly we will find out the areas of center and whole target.

For center;

Diameter = 5 in

Radius of circle is equal to half of the diameter.

radius = $\frac{diameter}{2}=\frac{5}{2}=2.5\ in$

Now we know that the area of circle is equal to π times square of the radius.

framing in equation form, we get;

Area = $\pi \times{2.5}^2$

For whole target;

Diameter = 25 in

Radius of circle is equal to half of the diameter.

radius = $\frac{diameter}{2}=\frac{25}{2}=12.5\ in$

Now we know that the area of circle is equal to π times square of the radius.

framing in equation form, we get;

Area = $\pi \times12.5^2$

Now to find the part of the center to the whole target we will divide Area of center with Area of the target.

framing in equation form we get;

the part of the center to the whole target = $\frac{\pi \times2.5^2}{\pi \times12.5^2}= \frac{6.25}{156.25} = \frac{1}{25}$

Hence the center is $\frac{1}{25}$ of the whole target.

6 0

3 years ago

Write the equation of a line that passes through (2,6) and (-2,2)

Viktor [21]

Answer:

y = x + 4

Step-by-step explanation:

The equation of the line is

y = mx + c

Step 1: find the slope

m = y2 - y1 / x2 - x1

Give points

( 2 , 6) ( -2 ,2)

x1 = 2

y1 = 6

x2 = -2

y2 = 2

m = 2 - 6 / -2 - 2

m = -4 / -4

m = 1

y = mx + c

y = 1x + c

y = x + c

Step 2: sub any of the two points given into the equation

( 2 , 6)

x = 2

y = 6

y = x + c

6 = 2 + c

6 - 2 = c

c = 4

Step 3: sub c into the equation

y = x + 4

The equation of the line is

y = x + 4

5 0

3 years ago