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Alik [6]
3 years ago
12

What is the probability of having an odd number in a single toss of a fair die.?

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
8 0
It will be 1/6 because it one side out of 6 tries
Bess [88]3 years ago
5 0
50% chance, theres 3 odd and 3 even on the die
You might be interested in
Simplify:<br><br> 20 - 2 × 8 + 42<br> A. <br> 20<br> B. <br> 160<br> C. <br> 52<br> D. <br> 26
Gnom [1K]

Answer: 46

Step-by-step explanation:

You can simplify this using PEMDAS:

Parentheses

Exponents

Multiplication/division

Addition/subtraction

Move through the steps in that order.

In this case, the first two steps are absent, so multiply first:

20 - 16 + 42

Then, add and subtract:

46.

5 0
4 years ago
Write an explicit formula for the sequence and find the 18th term.<br> -4, 12, -36...
Molodets [167]

Answer:

an = -4 * (-3)^ (n-1)

513560652

Step-by-step explanation:

We can find the common ratio

12/-4 = -3

r =-3

The explicit formula is

an =a1 r^(n-1)

an = -4 * (-3)^ (n-1)

We want the 18 th term

a 18 = -4 (-3) ^ 17

        513560652

4 0
3 years ago
Read 2 more answers
A new element with atomic number 116 was discovered in 2000. In 2012 it was named livermorium, Lv. Although Lv is radioactive an
allsm [11]

Answer:

7s²7p⁴

Step-by-step explanation:

Livermorium is located in the seventh period and sixteenth column of the periodic table. The noble gas configuration for livermorium is [Rn]7s²5f¹⁴6d¹⁰7p⁴. The valence electrons are the ones in the orbitals with the highest quantum number (coefficient). Remember, there can be up to 8 valence electrons at one time. Therefore, the valence electron configuration is 7s²7p⁴.

6 0
2 years ago
Read 2 more answers
PLEASE HELP (30 POINTS) Solve the rational equation x/3 = x^2/x + 5 , and check for extraneous solutions.
anygoal [31]

Option C: x=0 and x=\frac{5}{2} are the solutions.

Explanation:

The equation is \frac{x}{3} =\frac{x^{2} }{x+5}

We shall determine the value of x, by simplifying the equation.

$\begin{aligned} x(x+5) &=3 x^{2} \\ x^{2}+5 x &=3 x^{2} \\ 2 x^{2}-5 x &=0 \\ x(2 x-5) &=0 \end{aligned}$

Thus, x=0 and x=\frac{5}{2} are the solutions.

Now, let us check whether the solutions are extraneous solutions.

Let us substitute x=0 in the original equation to check whether both sides of the equation are equal.

\begin{aligned}&\frac{0}{3}=\frac{0^{2}}{0+5}\\&0=\frac{0}{5}\\&0=0\end{aligned}

Thus, both sides of the equation are equal.

Hence x=0 is a true solution.

Now, Let us substitute x=\frac{5}{2} in the original equation to check whether both sides of the equation are equal.

\begin{aligned}\frac{\left(\frac{5}{2}\right)}{3} &=\frac{\left(\frac{5}{2}\right)^{2}}{\left(\frac{5}{2}\right)+5} \\\frac{5}{6} &=\frac{\left(\frac{25}{4}\right)}{\left(\frac{15}{2}\right)} \\\frac{5}{6} &=\frac{5}{6}\end{aligned}

Thus, both sides of the equation are equal.

Hence, x=\frac{5}{2} is a true solution.

Thus, solutions are not extraneous.

Hence, Option C is the correct answer.

8 0
3 years ago
Item: c = p(1 + ). What is the final cost of a $40 item after an 8% tax is applied?
Snowcat [4.5K]

40(0.08) = 3.2

3.2+40

Answer: 43.20

5 0
3 years ago
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