Answer:
Let O be the center of a circle whose radius is r cm , in which AB= 14 cm long
cord is at a distanceof 24 cm from O. Draw a perpendicular OD on AB , thus ,
OD= 24 cm.
In right angled triangle. ODB
OB^2 = OD^2+ DB^2
r^2 =(24)^2+(AB/2)^2 = 576+(14/2)^2
r^2 = 576+ 49=625
r = √625. =25 cm. Answer.
Answer:
Step-by-step explanation:
7
Answer:
Area = 25 square inches.
Step-by-step explanation:
Consider the large base triangle first. The height is 15 - 5 = 10
The base across is 10 (the length of the smaller stick).
The Area of that triangle is 1/2 * b * h
Area = 1/2 * 10 * 10 = 50
Now the smaller triangle is the same base (the smaller stick of 10) * the height of 5
Area = 1/2 b * h
Area = 1/2 10 * 5
Area = 25
total area of the kite = 50 + 25 = 75
The reference angle for 240° is 60° because 240 is in quadrant III. If you were to subtract 240 from 180 you’d get 60.