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kondaur [170]
3 years ago
14

I need help ASAP answers 0.5 8 40 45

Mathematics
1 answer:
creativ13 [48]3 years ago
7 0

Answer:

Step-by-step explanation: why do  you  did the answer

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The manager of a bookstore wants to predict Sales from Number of Sales People Working using the accompanying data set. What is t
NemiM [27]

Answer:

n=5 \sum x = 103, \sum y = 177, \sum xy= 2088, \sum x^2 =1379, \sum y^2 =3359  

And in order to calculate the correlation coefficient we can use this formula:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}

r=\frac{10(2088)-(103)(177)}{\sqrt{[10(1379) -(103)^2][10(3359) -(177)^2]}}=0.9877

So then the correlation coefficient would be r =0.9877

And the determination coefficient for this case would be:

r^2 = 0.9877^2 = 0.9757 = 97.57 \%

And the correct option for this case would be:

A. The value of Upper R squared is 97.57​%, which is the percentage of variance in Sales that can be accounted for by the regression of Sales on Number of Sales People working.

Step-by-step explanation:

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

For this case we have the following data:

N. sal. peop.  work.            Sales (in $1000)

2                                                  10

3                                                  12

6                                                  14

8                                                  15

10                                                 17

10                                                 19

11                                                  19

16                                                 23

17                                                 23

20                                                25

We assume that the Number of Sales represent (X) and Sales (in $1000) represent (Y), we have this:

n=5 \sum x = 103, \sum y = 177, \sum xy= 2088, \sum x^2 =1379, \sum y^2 =3359  

And in order to calculate the correlation coefficient we can use this formula:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}

r=\frac{10(2088)-(103)(177)}{\sqrt{[10(1379) -(103)^2][10(3359) -(177)^2]}}=0.9877

So then the correlation coefficient would be r =0.9877

And the determination coefficient for this case would be:

r^2 = 0.9877^2 = 0.9757 = 97.57 \%

And the correct option for this case would be:

A. The value of Upper R squared is 97.57​%, which is the percentage of variance in Sales that can be accounted for by the regression of Sales on Number of Sales People working.

5 0
3 years ago
HELP me on 14 please :)
marshall27 [118]
Since there are 7 days in a week it would make sense to divide 56 by 7. This would be week 8.
7 0
3 years ago
What is the quotient when x3 − 5x2 + 3x − 8 is divided by x − 3?
brilliants [131]
X^3 - 5x^2 + 3x - 8/x - 3
Steps
First, divide x^3 - 5x^2 + 3x - 8/x - 3: x^3 - 5x^2 + 3x - 8/x - 3 = x^2 + -2x^2 + 3x -8/x - 3
= x^2 + -2x^2 + 3x - 8/x - 3
Second, divide -2x^2 + 3x - 8/x - 3: -2x^2 + 3x - 8/x - 3 = -2x + -3x - 8/x - 3
= x^2 - 2x + -3x - 8/x - 3
Third, divide -3x - 8/x - 3: -3x - 8/x - 3 = -3 + -17/x - 3
= x^2 - 2x - 3 + -17/x - 3
Lastly, simplify
= x^2 - 2x - 3 - 17/x - 3
6 0
3 years ago
I am not sure how to solve this could anyone help???
faltersainse [42]

Answer:

about 137 degrees

Step-by-step explanation:

see attached picture

6 0
3 years ago
Which is the graph of y = 2.5x?<br><br> A.<br><br><br> B.<br><br><br> C.<br><br><br> D.
Thepotemich [5.8K]
The answer is D. because first you got solve the problem.

y=2.5x
(turn y to 0)
0= 2.5x
÷2.5  ÷2.5
_________
0=x

So we got one answer (0,0) 

y=2.5x
(turn x to 0)
y= 2.5(0)
 y=2.5

(2.5, 0)

When you do (0,0) (2.5,0) on the graph it will look like D.)
5 0
3 years ago
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